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python - 汇总列表中的信息

问题描述

假设我有一个清单：

INPUT=[{'id': 1, 'context': 'this is q1', 'content': 'this is ch1'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch2'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch3'}, 
{'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

兑换：

OUTPUT=[{'id': 1, 'context': 'this is q1', 'content': ['this is ch1','this is ch2','this is ch3']},

{'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

python执行上述转换的最简单方法是什么？

标签： pythonpython-3.xlistdictionary

解决方案

Using itertools.groupby

Demo:

from itertools import groupby

INPUT=[{'id': 1, 'context': 'this is q1', 'content': 'this is ch1'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch2'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch3'}, 
{'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

res = []
for key, group in groupby(INPUT, lambda x: (x["id"])):
    temp = []
    for thing in group:
        temp.append(thing["content"])
    res.append({"id": key, "context": thing["context"], 'content': temp})
print(res)

Output:

[{'content': ['this is ch1', 'this is ch2', 'this is ch3'], 'id': 1, 'context': 'this is q1'}, {'content': ['this is ch14'], 'id': 2, 'context': 'this is q12'}]

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