首页 > 解决方案 > 如何获取我的音节,以便我可以控制台记录它们

问题描述

JSON 看起来像这样:

{
"main_object": {
"id": "new",
"getExerciseTitle": "TestAfterCodeCleaning",
"language": "nl_NL",
"application": "lettergrepen",
"main_object": {
  "title": "TestAfterCodeCleaning",
  "language": "nl_NL",
  "exercises": [
    {
      "word": "testikels",
      "syllables": [
        "test",
        "ikels",
        "",
        ""
      ]
    }
  ]
},
"dataType": "json"
 }
}

这就是我尝试获取的方式,syllables以便我可以获取console.log()它们:

var jsyl = json.main_object.main_object.exercises.syllables;

但是问题是:这显示在我的console.log()未定义中。为什么以及如何?

完整的代码如下所示:

function prepareCheck() {
$.getJSON('json_files/jsonData_' + ID + '.json', function(json) {
  $(document).on('keyup', '.syl-input', function() {
    var syllableval = $(idsyll).val();
     var jsyl = json.main_object.main_object.exercises.syllables;
  });
});
}

注意:JSON 有一个syllables,因为我认为它会更容易阅读,但是应该做些什么来获取所有syllables(如果有一个以上的数组syllables)。

标签: javascriptjquery

解决方案


在这种情况下,使用exercises[0]而不是exercises因为exercises是一个对象数组,在 index 处只有一个项目0

var jsyl = json.main_object.main_object.exercises[0].syllables;

var json = {
"main_object": {
"id": "new",
"getExerciseTitle": "TestAfterCodeCleaning",
"language": "nl_NL",
"application": "lettergrepen",
"main_object": {
  "title": "TestAfterCodeCleaning",
  "language": "nl_NL",
  "exercises": [
    {
      "word": "testikels",
      "syllables": [
        "test",
        "ikels",
        "",
        ""
      ]
    }
  ]
},
"dataType": "json"
 }
}

var jsyl = json.main_object.main_object.exercises[0].syllables;

console.log(jsyl); // [ 'test', 'ikels', '', '' ]


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