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java - Twitter4j：Oauth 不起作用

问题描述

努力获得一个工作的 twitter4j 实例，但在 Oauth 上遇到问题。我多次复制粘贴，创建了不同的应用程序和密钥/令牌，但仍然无法正常工作。我真的能在这里做错什么吗？

我的主要：

public class Main {

public static void main(String[] args) {
// write your code here

    Tweeter tweet = new Tweeter();
    try{
        tweet.searchTweets();

    } catch (TwitterException e) {
            e.printStackTrace();
        }
}
}

我的推特课：

public class Tweeter {

public static Twitter GetTwitterInstance(){

    String consumerKey = "**************";
    String consumerSecret = "*************";
    String accessToken = "***************";   // yourt token
    String accessTokenSecret = "************"; // your token secre

    ConfigurationBuilder cb = new ConfigurationBuilder();
    cb.setDebugEnabled(true)
            .setOAuthConsumerKey(consumerKey)
            .setOAuthConsumerSecret(consumerSecret)
            .setOAuthAccessToken(accessToken)
            .setOAuthAccessTokenSecret(accessTokenSecret);

    TwitterFactory tf = new TwitterFactory(cb.build());
    Twitter twitter = tf.getSingleton();

    return twitter;
}

public static void searchTweets() throws TwitterException{

    Twitter twitter = GetTwitterInstance();
    Query query = new Query("something");
    QueryResult result = twitter.search(query);
    List<Status> statuses = result.getTweets();

    for(Status tweet: statuses){
        System.out.println("User: "+tweet.getUser().getScreenName() + " Tweet: "+tweet.getText());
    }
}

}

和错误堆栈跟踪：

400:The request was invalid. An accompanying error message will explain why. 
This is the status code will be returned during version 1.0 rate 
limiting(https://dev.twitter.com/pages/rate-limiting). In API v1.1, a request 
without authentication is considered invalid and you will get this response.
message - Bad Authentication data.
code - 215

Relevant discussions can be found on the Internet at:
    http://www.google.co.jp/search?q=506c3b98 or
    http://www.google.co.jp/search?q=11ed9ae8
TwitterException{exceptionCode=[506c3b98-11ed9ae8], statusCode=400, 
message=Bad Authentication data., code=215, retryAfter=-1, 
rateLimitStatus=null, version=4.0.6}
    at twitter4j.HttpClientImpl.handleRequest(HttpClientImpl.java:164)
    at twitter4j.HttpClientBase.request(HttpClientBase.java:57)
    at twitter4j.HttpClientBase.get(HttpClientBase.java:75)
    at twitter4j.TwitterImpl.get(TwitterImpl.java:1786)
    at twitter4j.TwitterImpl.search(TwitterImpl.java:268)
    at Tweeter.searchTweets(Tweeter.java:58)
    at Main.main(Main.java:14)

打印 twitter 工厂的密钥/令牌会按预期提供正常的密钥/令牌，没有奇怪的字符或空格或其他任何东西。任何帮助将不胜感激！

标签： javatwitteroauthtwitter4j

解决方案

问题是显然tf.getSingleton()不返回twitter实例。

它应该是公正Twitter twitter = tf.getInstance();的，然后它就起作用了。

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