首页 > 解决方案 > 如何修复无法在未调用 Looper.prepare() 的线程内创建处理程序

问题描述

为什么我得到:Can't create handler inside thread that has not called Looper.prepare()这里的错误?

public class MovieInterface extends AsyncTask<String, Void, MovieResultsPage> {
    public Activity activity;

    MovieInterface(Activity context) {
        this.activity = context;
    }

    public void handleUpcomingMovies() {

    }

    @Override
    protected MovieResultsPage doInBackground(String... strings) {
        TmdbMovies movies = new TmdbApi("d2e5d02fe295efc00bad8da4dc384edf").getMovies();
        MovieResultsPage upcomingMovies = movies.getUpcoming(null, 1, "IN");
        int totalpages = upcomingMovies.getTotalPages();
        return upcomingMovies;
    }


    @Override
    protected void onPostExecute(final MovieResultsPage movieDbs) {
        super.onPostExecute(movieDbs);

                ArrayList<MovieClass> mymovielist = new ArrayList<>();
                for (MovieDb movieResult : movieDbs.getResults()) {
                    mymovielist.add(new MovieClass(movieResult.getTitle(), movieResult.getOverview()));
                }

                MovieAdapter movieClassArrayAdapter = new MovieAdapter(activity, R.layout.movie_list_item, mymovielist);

                ((ListView) activity.findViewById(R.id.upcomingMoviesList)).setAdapter(movieClassArrayAdapter);

    }

方法调用:

MovieInterface movieInterface = new MovieInterface(this) ;
movieInterface.execute() ;

正如其他类似问题的答案所暗示的那样,我没有在后台方法中进行任何 UI 更新。但仍然收到错误。

我是 android 和 java 的新手。我该如何解决 ?

标签: javaandroid

解决方案


new Handler(Looper.getMainLooper())

文档中的更多详细信息。


推荐阅读