json - 如何在纯批处理中解析 JSON

Question

我试图了解批处理文件中的 for 循环如何使用 /F "delims=" 选项但没有令牌遍历所有项目。我尝试了各种方法，但都失败了。首先，我知道还有其他方法可以读取 json 文件，但我只对学习如何在没有任何外部程序 jscript jq 等的情况下以纯批处理方式进行操作感兴趣。 JSon 格式如下所示，但项目数和顺序它们往往会有所不同。

{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
etc

但有时它可能只是：

"SomeVariableName2": "SomeString2", "SomeVariableName1": "SomeString1",

例如，我已经这样做了：

SetLocal DisableDelayedExpansion
For /F "delims=" %%c (file.json) Do(
REM iterate through each line
  set "Line=%%c"
  setlocal EnableDelayedExpansion
  set CR=CRLFCRLF
  Set "LineChange1=!Line:~1,-1!"
  for %%d in ("!CR!") do set LineChange2=!LineChange1:", "=%%~d!
  for %%e in (!LineChange4:CRLFCRLF= !) do set /a numtkns+=1
  REM but don't know how to insert the above numtkns in for options as it seems to require a function.
  set LineChange3=!LineChange2:": "==!
  set LineChange4=!LineChange3:"=!
  set /A Countr+=1
  REM this leaves this current line stored in variable LineChange4 as SomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeString
  )

或者，我可以使用换行符而不是 CRLFCRLF：

SetLocal DisableDelayedExpansion
For /F "delims=" %%c (file.json) Do(
REM iterate through each line
set "Line=%%c"
setlocal EnableDelayedExpansion
for /f %%d in ('copy /Z "%~dpf0" nul') do (
 set "CR=%%d"
)
Set "LineChange1=!Line:~1,-1!"
for %%e in ("!CR!") do set LineChange2=!LineChange1:", "=%%~e!
set LineChange3=!LineChange2:": "==!
set LineChange4=!LineChange3:"=!
set /A Countr+=1

)

这导致多行存储在变量 LineChange4 中：

SomeVariableName=SomeString
SomeVariableName=SomeString
SomeVariableName=SomeString
SomeVariableName=SomeString

如何遍历每个键值对并将每个值分配给与键同名的变量。我看过另一篇文章，他们确实设置了 var_%SomeVariableName%=SomeString 但它只适用于第一个键值对，我希望它遍历所有项目直到最后一个，即使令牌的数量和它们的顺序不同。

编辑： SomeString 可能是具有各种字符的标题，因此唯一近似已知的值是 SomeVariableName 键，它们往往没有空格。

Edit2：我最初并没有添加我还使用“Set”LineChange1=!Line:~1,-1!”来删除通常随 JSon 文件一起提供的花括号。

标签： jsonparsingbatch-filefor-looptoken

Answer 1

另一种更简单的方法：

@echo off
setlocal EnableDelayedExpansion

rem Read the lines of JSon file, removing braces
for /F "delims={}" %%a in (file.json) do (
   set "line=%%~a"
   rem Process each pair of "variable": "string" values
   for %%b in ("!line:": "==!") do echo SET %%b
)

使用这个输入文件：

{"SomeVariableName1": "Some String 1", "SomeVariableName2": "Some&String<2", "SomeVariableName3": "Some>String|3", "SomeVariableName4": "Some  String  4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}

...这是输出：

SET "SomeVariableName1=Some String 1"
SET "SomeVariableName2=Some&String<2"
SET "SomeVariableName3=Some>String|3"
SET "SomeVariableName4=Some  String  4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"