首页 > 解决方案 > 打印父数据以及嵌套 JSON 的子数据

问题描述

我有以下类型的 JSON。在另一个表中,我有 JSONPaths,它告诉我获取某些值。如果要获取子元素的值,则需要获取所有相应的父属性值并将所有这些值作为单行存储在数据框中。

{
  "Parent": {
    "Name": "Bob",
    "Age": "80",
    "Children": [
      {
        "Name": "Michael",
        "Gender":"M",
        "Children": [
          {
            "Name": "Ezee",
            "Gender": "M",
            "Age": 20
          },
          {
            "Name": "Ezee",
            "Gender": "M",
            "Age": 28,
            "Children": [
              {
                "Name": "Dre",
                "Age": 1
              },
              {
                "Name": "George",
                "Age": 2
              }
            ]
          }
        ],
        "Age": 50,
        "MiddleName": "Jay"
      },
      {
        "Name": "Justin",
        "Gender": "M",
        "Children": [
          {
            "Name": "Emily",
            "Age": 18,
            "Gender": "F"
          }
        ],
        "Age": 45
      }
    ]
  }
}

假设我需要获取 JSON 路径的值:Parent/Children/0/Children/0/Name,我需要获取相应父级(Parent/Children/0/[Name or Age or etc.])的名称、年龄等属性值并存储所有上述值作为单行。

目前,我可以通过传递相关路径分别获取父值,并通过传递该路径分别获取子值。

def findValue(path, json_data):
    paths = path.split("/")    
    data = json_data
    for i in range(0,len(paths)):
        if isinstance(data, list):
            paths[i]=int(paths[i])
            data = data[paths[i]]
        else:
            data = data.get(paths[i])
    return data

我怎么能做到这一点?

标签: pythonjson

解决方案


如果我理解得很好,你想要的只是一条路径,比如Parent/Children/0/Children/0/Name获取其父级相同属性的路径。在这种情况下,它将是Parent/Children/0/Name

这是我对python解释器的尝试,希望对您有所帮助:

>>> path = "Parent/Children/0/Children/0/Name"
>>> path_l = path.split('/')
>>> rev = path_l[::-1]
>>> rev
['Name', '0', 'Children', '0', 'Children', 'Parent']
>>> rev.index('Children')
2
>>> rev = rev[rev.index('Children')+1:]
>>> rev
['0', 'Children', 'Parent']
>>> final = rev[::-1] + [path_l[-1]]
>>> final
['Parent', 'Children', '0', 'Name']
>>> parent_path = '/'.join(final)
>>> parent_path
'Parent/Children/0/Name'

然后使用您的函数,您可以将两个值添加到数据框

>>> df = pandas.DataFrame({'Parent': [], 'Children':[]})
>>> df.append([parent], [children])

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