首页 > 解决方案 > 如何在单元测试中模拟 JPA 存储库的保存方法

问题描述

例如,我在 UserService 中有这个方法:

  @Override
  @Transactional
  public UserDto create(UserDto userDto) {

    User dbUser = userRepository.findOne(userDto.getId());

    if (dbUser != null) {
      throw new AuthException(AuthException.ErrorCode.DUPLICATE_USER_EXCEPTION);
    }

    User oneByLogin = userRepository.findOneByLogin(userDto.getLogin());
    if (oneByLogin != null) {
      throw new AuthExceptionAuthException.ErrorCode.DUPLICATE_LOGIN_EXCEPTION);
    }

    User newUser = new User();
    newUser.setGuid(UUID.randomUUID().toString());
    newUser.setInsertDate(new Date());
    newUser.setFirstName(userDto.getFirstName());
    newUser.setLastName(userDto.getLastName());
    newUser.setLogin(userDto.getLogin());
    newUser.setPassword(userDto.getPassword());
    newUser.setAuthToken(TokenGenerator.nextToken());
    newUser.setAuthTokenCreatedDate(new Date());

    User savedUser = userRepository.save(newUser);

    userDto.setAuthToken(savedUser.getAuthToken());
    log.info("User {0} created", savedUser.getLogin());
    return userDto;
  }

如何为此方法创建单元测试?我接下来尝试了:

  @Test
  public void createUser() {

    UserDto userDtoRequest = new UserDto();
    userDtoRequest.setLogin("Alex");
    userDtoRequest.setPassword("123");

    UserDto found = userService.create(userDtoRequest);
    assertThat(found.getAuthToken()).isNotEmpty();
}

我有下一个逻辑:

  1. 测试开始
  2. User dbUser = userRepository.findOne(userDto.getId());dbUser = NULL
  3. if (dbUser != null) 并if (oneByLogin != null)跳过
  4. 创建新用户并设置数据
  5. User savedUser = userRepository.save(newUser);已保存用户 = NULL

在这一步,我有一个问题,因为我不能模拟userRepository.save(newUser).

newUser create inside the method. and test fail.

savedUser.getAuthToken() - savedUser == NULL

我可以重写:

    userRepository.save(newUser);
    userDto.setAuthToken(newUser.getAuthToken());
    log.info("User {0} created", newUser.getLogin());
    return userDto;

但是如果我想使用返回的对象savedUser呢?

标签: javaspringunit-testingmockito

解决方案


你需要这样做。

when(userRepository.save(Mockito.any(User.class)))
                .thenAnswer(i -> i.getArguments()[0]);

现在您可以获得作为参数传递的用户。


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