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问题描述

我正在编写一个类来生成动态 SQL 插入查询。如果我还考虑作为自动增量值的 id ,那么我创建了一个包含七列的测试表,否则这些值只有六列。我试图测试我编写的插入函数是否有效,但控制台向我记录了一个关于有界变量数量的错误:PHP Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens. 通常我用来编写查询,这是我第一次收到此错误。是否有可能我还需要在查询中包含 id 列字段?这是代码:

测试页面

<?php
$dataManager = new DataManager($db);

$table = 'hats_info';
$data = array('test0','test1','test2','test3','test4','test5');
$columns = array('materialA','materialB','materialC','materialD','accessories','hat_image');
$holders = array('?','?','?','?','?','?');

echo $dataManager->insert($data, $table, $columns, $holders);

?> 

类方法代码

<?php 

public function insert($table, array $data, array $columns , array $holders){

    $columns = implode(', ', array_values($columns));
    $holders = implode(', ', array_values($holders));
    $values = implode(', ', array_values($data));

    $stmt = $this->db->prepare("INSERT INTO $table ($columns) VALUES ($holders)");
    return $stmt->execute(array($values));
}

?>

标签: phpooppdo

解决方案


我通过以下方式完成了这样的功能:

$table = 'hats_info';

$data = [
  'materialA' => 'test0',
  'materialB' => 'test1',
  'materialC' => 'test2',
  'materialD' => 'test3',
  'accessories' => 'test4',
  'hat_image' => 'test5'
];

echo $dataManager->insert($table, $data);

public function insert($table, array $data) {
    $columns_delimited = implode(', ' array_map(
        function ($column) { return "`$column`"; },
        array_keys($data)
    ));
    $placeholders = implode(', ', array_fill(1, count($data), '?'));
    $sql = "INSERT INTO `$table` ($columns_delimited) VALUES ($placeholders)"
    $stmt = $this->db->prepare($sql);
    return $stmt->execute(array_values($data));
}

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