r - R：如果向量构成列表的一部分，如何从向量中获取元素？

Question

我有两个清单：

myList1 <- list(c("","VNW","SPEC","N","BW" ), c("","WW","N","SPEC","ADJ"),c( "","WW","N"), c("","WW","N"), c("","ADJ","N","WW"), c( "","ADJ","N"))

myList2 <- list(c( "","125141","44","4945","3"), c("","114146","77","19","3"), c("","4359","695"), c("","1372","623"), c("","209","71","1"), c( "","33","3"))

我也有两种形式的索引：

MyNIndices <- c(4,3,3,3,3,3)

或者

MyNIndices <- list (4,3,3,3,3,3)

MyNIndices 反映了 MyList1 中每个向量上的哪个元素出现“N”？

现在，我希望能够索引到 myList2 上的相同索引，以便我可以获得与 N 对应的值。所以，我想作为输出

MyFinalValues <- c(4945, 77, 695, 623, 71, 3)

或者

MyFinalValues <- list(4945, 77, 695, 623, 71, 3)

我怎样才能做到这一点？

标签： r

Answer 1

在 tidyverse 你可以

library(purrr)
map2(myList2,MyNIndices, `[[`)

或者，如果你想要一个数字向量

map2_chr(myList2,MyNIndices, `[[`) %>% 
    as.numeric()