首页 > 解决方案 > Springboot:需要一个找不到的“javax.persistence.EntityManagerFactory”类型的bean

问题描述

我正在开发 Spring Boot 应用程序并在启动服务器时遇到此错误。我不确定我是否错误地定义了任何注释或缺少任何依赖项。任何帮助,将不胜感激。

主类:

@SpringBootApplication
@Configuration
@ComponentScan
@EnableAutoConfiguration

public class DemoApplication {

    public static void main(String[] args) {
        System.out.println("Hello world");
        SpringApplication.run(DemoApplication.class, args);
    }
}

用户服务类:

@Service
public class UserService implements IUserService {

    @Autowired
    private UserDAO userDAO;

    @Override
    public List<UserDTO> getAllUsers() {

        List<User> entities = userDAO.getUsers();
        List<UserDTO> users = new ArrayList<UserDTO>();//Will never use directly User Object, will be using Tranferable objects

        Iterator<User> iterator = entities.iterator();

        while(iterator.hasNext()) {
            User user = iterator.next();
            users.add(ApiDTOBuilder.userToUserDTO(user));//We are building UserDTO object.
        }
        return users;
    }

    @Override
    public UserDTO getUserByUsername(String username) {
        User user = userDAO.getUser(username);
        return ApiDTOBuilder.userToUserDTO(user);
    }

    @Override
    public void createUser(UserDTO user) {
        userDAO.createUser(ApiDTOBuilder.userDTOToUser(user));
    }

    @Override
    public void updateUser(UserDTO user) {
        userDAO.updateUser(ApiDTOBuilder.userDTOToUser(user));

    }

    @Override
    public void deleteUser(String username) {
        userDAO.deleteUser(username);
    }
}

UserDAO 类:

@Repository 公共类 UserDAO 实现 IUserDAO {

        @PersistenceContext
        EntityManager em;//JPA EntityManager is used to access a database in a particular application. It is used to manage persistent entity instances, to find entities by their primary key identity(As here is Username), and to query over all entities.

        @Override
        @Transactional
        public User getUser(String username) {
            return em.find(User.class, username); //Here entitymanager can find the username as it has the capability to find an entity by unique identifies
        }


        @Override
        @Transactional
        public List<User> getUsers() {
            List<User> resultList = em.createQuery("FROM user_tbl", User.class).getResultList();
            return resultList;
        }

        @Override
        @Transactional
        public void createUser(User user) {
            em.persist(user);//Make an instance managed and persistent.
        }

        @Override
        @Transactional
        public void updateUser(User user) {
            em.merge(user);//Merge the state of the given entity into the current persistence context.
        }

        @Override
        @Transactional
        public void deleteUser(String username) {
            User user = this.getUser(username);
            em.remove(user);//Remove the entity instance.
        }
}

构建.gradle:

buildscript {
    ext {
        springBootVersion = '2.0.0.RELEASE'
    }
    repositories {
        mavenCentral()
    }
    dependencies {
        classpath("org.springframework.boot:spring-boot-gradle-plugin:${springBootVersion}")
    }
}

apply plugin: 'java'
apply plugin: 'eclipse'
apply plugin: 'org.springframework.boot'
apply plugin: 'io.spring.dependency-management'

group = 'com.example'
version = '0.0.1-SNAPSHOT'
sourceCompatibility = 1.8

repositories {
    mavenCentral()
}


dependencies {
    compile('org.springframework.boot:spring-boot-starter-data-jpa')
    compile('org.springframework.boot:spring-boot-starter-web')
    compile('org.springframework.boot:spring-boot-starter-security')
    compile('org.hibernate.javax.persistence:hibernate-jpa-2.1-api:1.0.0.Final')
    compile('javax.xml.bind:jaxb-api:2.2.11')
    compile('org.springframework.boot:spring-boot-starter-test:2.0.2.RELEASE')
    compile('com.sun.xml.bind:jaxb-core:2.2.11')
    compile('com.sun.xml.bind:jaxb-impl:2.2.11')
    runtime('org.springframework.boot:spring-boot-devtools')
    runtime('mysql:mysql-connector-java')
    testCompile('org.springframework.boot:spring-boot-starter-test')
}

错误信息:

***************************
APPLICATION FAILED TO START
***************************
Description:

Field userDAO in com.example.demo.service.UserService required a bean of type 'javax.persistence.EntityManagerFactory' that could not be found.
Action:

Consider defining a bean of type 'javax.persistence.EntityManagerFactory' in your configuration.

我看到了所有相关的答案并尝试实施这些建议,例如添加依赖项、在主类中添加符号等。但它显示了相同的错误。请有人帮助我。先感谢您。

PS:我的应用程序的 Github 链接:https ://github.com/heliOpenxCell/demo

标签: springhibernatespring-mvcspring-bootspring-data-jpa

解决方案


我遇到了同样的问题,只需将其添加到您的 Maven 或 gradle 中,它对我有用!

马文:

<dependency>
  <groupId>org.apache.tomcat</groupId>
  <artifactId>tomcat-jdbc</artifactId>
  <version>9.0.10</version>
</dependency>

摇篮:

compile group: 'org.apache.tomcat', name: 'tomcat-jdbc', version: '9.0.10'

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