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php - PHP：在数组 1 深度到多深度 json 之间转换

问题描述

我像这样保持数据 1 深（也许保留在数据库中）

$data = [
    "games" => "",
    "games>sport" => "",
    "games>sport>enabled" => true,
    "feature" => "",
    "feature>register" => "",
    "feature>register>enabled" => true,
    "contact" => "",
    "contact>tel" => "",
    "contact>tel>lang" => "th",
    "contact>tel>number" => "012345678"
];

然后转换为 json

结果：

{
  "games": {
    "sport":
      "enabled": true
    }
  },
  "feature": {
    "register": {
      "enabled": true,
      "captcha": true
    }
  },
  "contact": {
    "tel": {
      "lang": "th",
      "number": "012345678"
    }
  }

}

编辑：将其标记为与未关闭事件的文章重复的人。我必须找到我的路

这是我自己的答案。

$col = [];
foreach($data as $key => $val) {
    $ex = explode(">", $key);
    $cnt = count($ex);

    if (count($ex) > 5) { die('Maximum deep is 5'); }
    if ($cnt == 1) { $col[$ex[0]] = $val;  }
    if ($cnt == 2) { $col[$ex[0]][$ex[1]] = $val;  }
    if ($cnt == 3) { $col[$ex[0]][$ex[1]][$ex[2]] = $val; }
    if ($cnt == 4) { $col[$ex[0]][$ex[1]][$ex[2]][$ex[3]] = $val; }
    if ($cnt == 5) { $col[$ex[0]][$ex[1]][$ex[2]][$ex[3]][$ex[4]] = $val; }
}
die(json_encode($col));

标签： phpjsonexplode

解决方案

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