php - 在PHP中显示多个表中的外键

问题描述

我目前正在开发一个简单的搜索网站。我正在使用 php 和 mysql 工作台。我的问题是在下面的文章页面中，我无法显示位置和供应商的实际名称，它们位于不同的表中，但通过我的“复制”表中的外键连接。它只显示与实际单词对应的首字母缩写词和数字。对不起，我的英语不好。我将插入一张我的 er 图表的图片。

ER图在这里：

ER图在这里

搜索页面：

<?php
    include 'header.php';
?>

<div id= "Title">
    <h1>Online Public Access Catalog</h1>
</div>

<div id="navbar">
    <h2> DISCOVERY SERVICE</h2>
    <form id="SearchBar" action="search.php" method="POST">
        <input type="text" name="search" class="search" placeholder="Search Here">
        <button type="submit" name="submit" class= "submit">Submit</button> 
</form>
<h3 class="enterword"> Enter a word or phrase and press submit</h3>

</body>
</html>

搜索结果页面：

<?php
    include 'header.php'
?>

<h1 class="searchresults">Search Results:</h1>

<div class="search-container">
    <?php
    if (isset($_POST['submit']))
    {
        $search = mysqli_real_escape_string($conn, $_POST['search']);
        $sql = "SELECT * FROM book WHERE Book_Title LIKE '%$search%' OR Author LIKE '%$search%' OR Call_Number LIKE '%$search%'";
        $result = mysqli_query($conn, $sql);
        $queryResult = mysqli_num_rows($result);

        echo "<h3 class='resultcount'>There are ".$queryResult." results!</h3>";

        if ($queryResult > 0)
        {
            while ($row = mysqli_fetch_assoc($result))
            {
                echo "<a href='article.php?Book_Title=".$row['Book_Title']."&id=".$row['Book_ID']."' class= 'search-ref'><div class=search-box>
                <tr><td>".$row['Book_Title']." </td>
                <td>/ ".$row['Author']."</td>
                <p>".$row['Call_Number']."</p>
                </div></tr><br>";
            }

        }
    }
    ?>
    <input type="button" value="Back" onclick="history.back(-1)" />
</div>

<!-- Article Page -->
<?php
    include 'header.php';
?>

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>

<div class="article-container">


<?php
//Declairing Variables
$Author = "Authors: ";
$Edition = "Edition: ";
$Subject ="Subject: ";
$Summary = "Summary: ";
$Notes = "Notes: ";
$Publisher ="Publisher: ";
$Phys_Desc ="Physical Description: ";
$Call_Number ="Call Number: ";
$Book_ID = "Book ID: ";


$Title= mysqli_real_escape_string($conn, $_GET['Book_Title']);

$sql ="SELECT * FROM book WHERE Book_Title='$Title'";
$result = mysqli_query($conn, $sql);      
$queryResult = mysqli_num_rows($result);

if ($queryResult > 0)
while ($row = mysqli_fetch_assoc($result))
{
echo "<div class= 'article-box'>
    <h3 class='booktitle'><b>".$row['Book_Title']."</h3></b>
    <p><b>$Author</b>".$row['Author']."</p>
    <p><b>$Edition</b>".$row['Edition']."</p>
    <p><b>$Subject</b>".$row['Subject']."</p>
    <p><b>$Summary</b>".$row['Summary']."</p>
    <p><b>$Notes</b>".$row['Notes']."</p>
    <p><b>$Publisher</b>".$row['Publisher']."</p>
    <p><b>$Phys_Desc</b>".$row['Phys_Desc']."</p>
    <p><b>$Call_Number</b>".$row['Call_Number']."</p>
</div>";
}
?>
<input type="button" value="Back" onclick="history.back(-1)" />
<!-- POP-UP WINDOW -->
  <!-- Trigger the modal with a button -->
  <button type="button" class="btn btn-info btn-lg" data-toggle="modal" data-target="#myModal">Copies</button>

  <!-- Modal -->
  <div class="modal fade" id="myModal" role="dialog">
    <div class="modal-dialog">

      <!-- Modal content-->
      <div class="modal-content">
        <div class="modal-header">
          <button type="button" class="close" data-dismiss="modal">&times;</button>
          <h4 class="modal-title">Copies</h4>
        </div>
        <div class="modal-body">
        <table class = "table">
    <tr>
        <th>Barcode</th>
        <th>Copy</th>
        <th>Status</th>
        <th>Location</th>
        <th>Format</th>
        <th>Vendor</th>
    </tr>
          <?php
  {
    $id = mysqli_real_escape_string($conn, $_GET['id']);

    $sql = "SELECT * FROM copy WHERE Book_ID='$id'";

    $result = mysqli_query($conn, $sql);
    $queryResult = mysqli_num_rows($result);

    if ($queryResult > 0)
    {
      while ($row = mysqli_fetch_assoc($result))
      {

        echo "
        <tr><td>".$row['Barcode']."</td>
        <td>".$row['Copy']."</td>
        <td>".$row['Status']."</td>
        <td>".$row['Location']."</td>
        <td>".$row['Format']."</td>
        <td>".$row['Vendor']."</td></tr>
        ";
      }

    }

  }
  ?>

        </div>
      </div>

    </div>

  </div>

</div>

</body>
</html>

标签： phphtmlmysql

php - 在PHP中显示多个表中的外键

问题描述

解决方案

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