首页 > 解决方案 > 如何使用 Kotlin 和 jackson ObjectMapper 从 json 中删除属性

问题描述

我想删除以下 JSON 中所有出现的“attributeToRemove”:

{
    "Item994": [
        {
            "attributeToRemove": {
                "someItem": null
            },
            "types": [
                "type194",
                "type294"
            ],
            "p1": "SOS"
        }
    ],
    "Item99": [
        {
            "attributeToRemove": {
                "someItem": null
            },
            "types": [
                "type19",
                "type29"
            ],
            "p1": "SOS"
        }
    ]
}

我尝试使用removeAll但我保留此错误:Type mismatch: inferred type is (JsonNode!) -> JsonNode! but (JsonNode!) -> Boolean was expected

谁能建议如何解决这个问题?

这是我的代码:

import com.fasterxml.jackson.databind.ObjectMapper

    fun main ( args : Array < String > ) {

        val someString = "{\n" +
                "    \"Item994\": [\n" +
                "        {\n" +
                "            \"attributeToRemove\": {\n" +
                "                \"someItem\": null\n" +
                "            },\n" +
                "            \"types\": [\n" +
                "                \"type194\",\n" +
                "                \"type294\"\n" +
                "            ],\n" +
                "            \"p1\": \"SOS\"\n" +
                "        }\n" +
                "    ],\n" +
                "    \"Item99\": [\n" +
                "        {\n" +
                "            \"attributeToRemove\": {\n" +
                "                \"someItem\": null\n" +
                "            },\n" +
                "            \"types\": [\n" +
                "                \"type19\",\n" +
                "                \"type29\"\n" +
                "            ],\n" +
                "            \"p1\": \"SOS\"\n" +
                "        }\n" +
                "    ]\n" +
                "}"
        val mapper = ObjectMapper()
        val jsonStr = mapper.writerWithDefaultPrettyPrinter()
                .writeValueAsString(someString)

        val jsonResult = mapper.readTree(someString)
        jsonResult.removeAll { it.get("attributeToRemove") }

    }

标签: javakotlinjackson-databind

解决方案


将 jsonString 转换为 Object,忽略要删除的字段,然后映射回 jsonString:

import com.google.gson.Gson
import com.google.gson.annotations.SerializedName

class Item99 {
    var p1: String? = null
    var types: Array<String>? = null
}

class Item994 {
    var p1: String? = null
    var types: Array<String>? = null
}

class Wrapper (
        @SerializedName("Item99")
        var item99: Array<Item99>?,
        @SerializedName("Item994")
        var item994: Array<Item994>?
)

object Main {

    var jsonString = "{\n" +
            "    \"Item994\": [\n" +
            "        {\n" +
            "            \"attributeToRemove\": {\n" +
            "                \"someItem\": null\n" +
            "            },\n" +
            "            \"types\": [\n" +
            "                \"type194\",\n" +
            "                \"type294\"\n" +
            "            ],\n" +
            "            \"p1\": \"SOS\"\n" +
            "        }\n" +
            "    ],\n" +
            "    \"Item99\": [\n" +
            "        {\n" +
            "            \"attributeToRemove\": {\n" +
            "                \"someItem\": null\n" +
            "            },\n" +
            "            \"types\": [\n" +
            "                \"type19\",\n" +
            "                \"type29\"\n" +
            "            ],\n" +
            "            \"p1\": \"SOS\"\n" +
            "        }\n" +
            "    ]\n" +
            "}"

    @JvmStatic
    fun main(args: Array<String>) {
        val gson = Gson()
        val wrapper = gson.fromJson(jsonString,Wrapper::class.java)
        println(gson.toJson(wrapper))

    }
}

输出将如下所示:

{"Item99":[{"p1":"SOS","types":["type19","type29"]}],"Item994":[{"p1":"SOS","types":[ "type194","type294"]}]}


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