首页 > 解决方案 > 在循环内修改 Tensorflow 变量

问题描述

我想在 while 循环中修改变量的某些索引。基本上将下面的python代码转换为Tensorflow:

import numpy
tf_variable=numpy.zeros(10,numpy.int32)
for i in range (10):
    tf_variable[i]=i
tf_variable

Tensorflow 代码如下所示:除了它给出错误

import tensorflow as tf
var=tf.get_variable('var',initializer=tf.zeros([10],tf.int32),trainable=False)
itr=tf.constant(0)
sess=tf.Session()
sess.run(tf.global_variables_initializer()) #initializing variables


print('itr=',sess.run(itr))
def w_c(itr,var):
    return(tf.less(itr,10))
def w_b(itr,var):
    var=tf.assign(var[1],9) #lets say i want to modify index 1 of variable var
    itr=tf.add(itr,1)
    return [itr,var] #these tensors when returning actually get called


OP=tf.while_loop(w_c,w_b,[itr,var],parallel_iterations=1,back_prop=False)
print(sess.run(OP))

谢谢

标签: python-3.xtensorflowwhile-loop

解决方案


在 CPU 上“绕道”并不总是可行的(你会失去梯度)。以下是如何在 TensorFlow 中实现您的 numpy 示例的可能性(受这篇文章和我在一篇文章中给出的答案的启发)

import tensorflow as tf

tf_variable = tf.Variable(tf.ones([10]))

def body(i, v):
    index = i
    new_value = tf.to_float(i)
    delta_value = new_value - v[index:index+1]
    delta = tf.SparseTensor([[index]], delta_value, (10,))
    v_updated = v + tf.sparse_tensor_to_dense(delta)
    return tf.add(i, 1), v_updated


_, updated = tf.while_loop(lambda i, _: tf.less(i, 10), body, [0, tf_variable])

with tf.Session() as sess:
    sess.run(tf.global_variables_initializer())
    print(sess.run(tf_variable))
    print(sess.run(updated))

这打印

[1. 1. 1. 1. 1. 1. 1. 1. 1. 1.]
[0. 1. 2. 3. 4. 5. 6. 7. 8. 9.]

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