csv - Jmeter JSR223 采样器 - 无法将数据写入 CSV 文件
问题描述
我正在使用 Jmeter v 4.0 r1823414。根据这个答案,有一个使用 JSR223 PostProcessor 的建议,逐字记录:
建议将 Groovy 用于任何形式的脚本以考虑迁移到 JSR223 PostProcessor
在这种方法之前,我尝试使用 BeanShell Sampler 将数据简单地写入 csv 文件。我从blazemeter 教程页面获取的代码示例。但是,我遇到了错误
Sourced file: inline evaluation of: ``import java.io.FileWriter; import java.util.Arrays; import java.io.Writer; impor . . . '' : Typed variable declaration : Attempt to access property on undefined variable or class name
好吧,既然有人建议转移到JSR223 Sampler(或 PostProcessor,不确定它们在功能方面有什么区别),我稍微修改了代码,使其更加基于 Java,以便在JSR223 Sampler中使用:
import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;
public class Main {
//Default separator
private static char SEPARATOR = ',';
//get path of csv file (creates new one if its not exists)
private static String csvFile = "C:/TiredOfProgramming/Work/results.csv"; // for example '/User/Downloads/blabla.csv'
private static String[] params = {"hello", "world", "jmeter"};
//function write line in csv
private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
{
boolean firstParameter = true;
StringBuilder stringBuilder = new StringBuilder();
String parameter = " ";
for (int i = 0; i < parameters.length; i++)
{
//get param
parameter = parameters[i];
log.info(parameter);
//if the first param in the line, separator is not needed
if (!firstParameter)
{
stringBuilder.append(separator);
}
//Add param to line
stringBuilder.append(parameter);
firstParameter = false;
}
//prepare file to next line
stringBuilder.append("\n");
//add to file the line
log.info(stringBuilder.toString());
writer.append(stringBuilder.toString());
}
FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);
//proper close to file
fileWriter.flush();
fileWriter.close();
}
此特定脚本失败并显示以下消息:
Script8.groovy: 15: 意外令牌: hello @ line 15, column 39. private static String[] params = {"hello", "world", "jmeter"};
如果我在IntelliJ IDE中测试这个,只需将 writeLine 方法包装到 main 方法中,一切正常
package com.tiredofprogramming;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;
public class Main {
//Default separator
private static char SEPARATOR = ',';
//get path of csv file (creates new one if its not exists)
private static String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'
private static String[] params = {"hello", "world", "jmeter"};
public static void main(String[] args) throws IOException {
FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);
//proper close to file
fileWriter.flush();
fileWriter.close();
}
//function write line in csv
private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
{
boolean firstParameter = true;
StringBuilder stringBuilder = new StringBuilder();
String parameter = " ";
for (int i = 0; i < parameters.length; i++)
{
//get param
parameter = parameters[i];
System.out.println(parameter);
//if the first param in the line, separator is not needed
if (!firstParameter)
{
stringBuilder.append(separator);
}
//Add param to line
stringBuilder.append(parameter);
firstParameter = false;
}
//prepare file to next line
stringBuilder.append("\n");
//add to file the line
System.out.println(stringBuilder.toString());
writer.append(stringBuilder.toString());
}
}
我的问题是:groovy 采样器是否理解 Java(在我看到的一篇 SO 帖子中提到 Groovy 理解 99% 的 Java 语法)。有没有人成功地使用 Jmeter 将数据写入 csv 文件?
解决方案
试试这个轻微的修改:
//Default separator
char SEPARATOR = ',';
//get path of csv file (creates new one if its not exists)
String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'
def params = ["hello", "world", "jmeter"];
//function write line in csv
def writeLine(FileWriter writer, List<String> parameters, char separator) throws IOException {
boolean firstParameter = true;
StringBuilder stringBuilder = new StringBuilder();
String parameter = " ";
for (int i = 0; i < parameters.size(); i++) {
//get param
parameter = parameters[i];
log.info(parameter);
//if the first param in the line, separator is not needed
if (!firstParameter) {
stringBuilder.append(separator);
}
//Add param to line
stringBuilder.append(parameter);
firstParameter = false;
}
//prepare file to next line
stringBuilder.append("\n");
//add to file the line
log.info(stringBuilder.toString());
writer.append(stringBuilder.toString());
}
FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);
//proper close to file
fileWriter.flush();
fileWriter.close();
然而,在 Groovy 中有更简单的方法可以实现相同的目标,请查看:
推荐阅读
- amazon-web-services - s3fs 不会将下载的文件存储在指定的缓存目录中
- javascript - 返回顶部按钮行为
- c# - 阅读 IBatisNet 准备好的 sql xml 语句
- javascript - 如何禁用从扩展文件导入
- flutter - 颤振图像过滤器无法使用 image_editor_pro
- android - 什么是 gradle 任务 extractAfatDebugNativeDebugMetadata?
- automation - 如何在 jira 中创建史诗 - jira 中的史诗
- php - 无法加载 PEM 客户端证书,在 PHP 中调用 SOAP 服务时出现 OpenSSL 错误
- android - 获取 Intent 的内容 (Android)
- time-complexity - 从方程确定比较次数(快速排序)