首页 > 解决方案 > Jmeter JSR223 采样器 - 无法将数据写入 CSV 文件

问题描述

我正在使用 Jmeter v 4.0 r1823414。根据这个答案,有一个使用 JSR223 PostProcessor 的建议,逐字记录:

建议将 Groovy 用于任何形式的脚本以考虑迁移到 JSR223 PostProcessor

在这种方法之前,我尝试使用 BeanShell Sampler 将数据简单地写入 csv 文件。我从blazemeter 教程页面获取的代码示例。但是,我遇到了错误

Sourced file: inline evaluation of: ``import java.io.FileWriter; import java.util.Arrays; import java.io.Writer; impor . . . '' : Typed variable declaration : Attempt to access property on undefined variable or class name

好吧,既然有人建议转移到JSR223 Sampler(或 PostProcessor,不确定它们在功能方面有什么区别),我稍微修改了代码,使其更加基于 Java,以便在JSR223 Sampler中使用:

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:/TiredOfProgramming/Work/results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            log.info(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        log.info(stringBuilder.toString());
        writer.append(stringBuilder.toString());
    }

        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);

        //proper close to file
        fileWriter.flush();
        fileWriter.close();
}

此特定脚本失败并显示以下消息:

Script8.groovy: 15: 意外令牌: hello @ line 15, column 39. private static String[] params = {"hello", "world", "jmeter"};

如果我在IntelliJ IDE中测试这个,只需将 writeLine 方法包装到 main 方法中,一切正常

package com.tiredofprogramming;

import java.io.FileWriter;
import java.io.IOException;
import java.util.Arrays;
import java.io.Writer;
import java.util.List;

public class Main {

    //Default separator
    private static char SEPARATOR = ',';

    //get path of csv file (creates new one if its not exists)
    private static String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

    private static String[] params = {"hello", "world", "jmeter"};

    public static void main(String[] args) throws IOException {
        FileWriter fileWriter = new FileWriter(csvFile, true);
        writeLine(fileWriter, params, SEPARATOR);
        //proper close to file
        fileWriter.flush();
        fileWriter.close();
    }


    //function write line in csv
    private static void writeLine(FileWriter writer, String[] parameters, char separator) throws IOException
    {
        boolean firstParameter = true;
        StringBuilder stringBuilder = new StringBuilder();
        String parameter = " ";

        for (int i = 0; i < parameters.length; i++)
        {
            //get param
            parameter = parameters[i];
            System.out.println(parameter);

            //if the first param in the line, separator is not needed
            if (!firstParameter)
            {
                stringBuilder.append(separator);
            }

            //Add param to line
            stringBuilder.append(parameter);

            firstParameter = false;
        }

        //prepare file to next line
        stringBuilder.append("\n");

        //add to file the line
        System.out.println(stringBuilder.toString());
        writer.append(stringBuilder.toString());

  }
}

我的问题是:groovy 采样器是否理解 Java(在我看到的一篇 SO 帖子中提到 Groovy 理解 99% 的 Java 语法)。有没有人成功地使用 Jmeter 将数据写入 csv 文件?

标签: csvjmeterjsr223

解决方案


试试这个轻微的修改:

//Default separator
char SEPARATOR = ',';

//get path of csv file (creates new one if its not exists)
String csvFile = "C:\\TiredOfProgramming\\Work\\results.csv"; // for example '/User/Downloads/blabla.csv'

def params = ["hello", "world", "jmeter"];

//function write line in csv
def writeLine(FileWriter writer, List<String> parameters, char separator) throws IOException {
    boolean firstParameter = true;
    StringBuilder stringBuilder = new StringBuilder();
    String parameter = " ";

    for (int i = 0; i < parameters.size(); i++) {
        //get param
        parameter = parameters[i];
        log.info(parameter);

        //if the first param in the line, separator is not needed
        if (!firstParameter) {
            stringBuilder.append(separator);
        }

        //Add param to line
        stringBuilder.append(parameter);

        firstParameter = false;
    }

    //prepare file to next line
    stringBuilder.append("\n");

    //add to file the line
    log.info(stringBuilder.toString());
    writer.append(stringBuilder.toString());
}

FileWriter fileWriter = new FileWriter(csvFile, true);
writeLine(fileWriter, params, SEPARATOR);

//proper close to file
fileWriter.flush();
fileWriter.close();

JMeter Groovy 创建 CSV

然而,在 Groovy 中有更简单的方法可以实现相同的目标,请查看:


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