javafx - 复选框松开他的状态

Question

我创建了一个包含 3 列的表。在中间栏中，我有 3 个复选框。当我的窗口初始化时，如果来自数据库的信息合适，则勾选复选框。有用。用户可以取消勾选数据库中更改信息的复选框。我的问题是，当我验证复选框是否被选中时，一次返回 true，一次返回 false，但复选框处于相同状态（选中与否）。

public CheckBox podglad2, edycja2, dodawanie2, usuwanie2, importowanie2, eksportowanie2, nadawanie2;


private static void setAccessLabelStyle2(CheckBox label, AccessLevel level, Integer value) {
    if (check(level, value)) {
        label.setSelected(true);
    } else {
        label.setSelected(false);
    }
}

private static boolean check(AccessLevel accessLevel, Integer value) {
    return (accessLevel.getBit() & value) > 0;
}


public TableCell getFunctionCell2(TableCell cell, Integer accessLevel) {
    HBox graphics = new HBox();
    graphics.setAlignment(Pos.CENTER_LEFT);
    graphics.setSpacing(7.0);

    podglad2 = new CheckBox("P");
    setAccessLabelStyle2(podglad2, AccessLevel.VIEW, accessLevel);

    dodawanie2 = new CheckBox("D");
    setAccessLabelStyle2(dodawanie2, AccessLevel.CREATE, accessLevel);

    edycja2 = new CheckBox("E");
    setAccessLabelStyle2(edycja2, AccessLevel.UPDATE, accessLevel);

}

accessLevelCol.setCellFactory(param -> {
        return new TableCell<FunctionTableModel, Integer>() {

            @Override
            protected void updateItem(Integer item, boolean empty) {
                super.updateItem(item, empty);
                if (item == null || empty) {
                    setText(null);
                    setStyle("");
                } else {
                    getFunctionCell2(this, item);

                    podglad2.setOnAction(e -> {
                        FunctionTableModel row = getTableView().getItems().get(getIndex());
                        if (check(AccessLevel.VIEW, row.getAccessLevel())) {
                            if (podglad2.isSelected() == false) {
                                row.setAccessLevel(row.getAccessLevel() - AccessLevel.VIEW.getBit());
                            }
                        } else {
                            if (podglad2.isSelected() == true) {
                                row.setAccessLevel(row.getAccessLevel() + AccessLevel.VIEW.getBit());
                            }
                        }
                    });
                    dodawanie2.setOnAction(e -> {

                        FunctionTableModel row = getTableView().getItems().get(getIndex());
                        if (check(AccessLevel.CREATE, row.getAccessLevel())) {
                            if (dodawanie2.isSelected() == false) {
                                row.setAccessLevel(row.getAccessLevel() - AccessLevel.CREATE.getBit());
                            }
                        } else {
                            if (dodawanie2.isSelected() == true) {
                                row.setAccessLevel(row.getAccessLevel() + AccessLevel.CREATE.getBit());
                            }
                        }
                    });
                    edycja2.setOnAction(e -> {
                        FunctionTableModel row = getTableView().getItems().get(getIndex());
                        if (check(AccessLevel.UPDATE, row.getAccessLevel())) {
                            if (edycja2.isSelected() == false) {
                                row.setAccessLevel(row.getAccessLevel() - AccessLevel.UPDATE.getBit());
                            }
                        } else {
                            if (edycja2.isSelected() == true) {
                                row.setAccessLevel(row.getAccessLevel() + AccessLevel.UPDATE.getBit());
                            }
                        }
                    });
                }

我该如何解决这个问题？

标签： javafxcheckboxtableview