ios - swift：在标签中显示秒数。

Question

我有这个秒数：

var modeLight = [5,30,60,30,60,30]

我有计时器：

@IBOutlet weak var timerLabel: UILabel!
var seconds = 60
var timer = Timer()
var isTimerRunning = false
var resumeTapped = false

@IBAction func startAction(_ sender: UIButton) {
    if isTimerRunning == false {
                    runTimer()
                }
}

func runTimer() {
        timer = Timer.scheduledTimer(timeInterval: 1, target: self, selector: (#selector(MasterViewController.updateTimer)), userInfo: nil, repeats: true)
        isTimerRunning = true
    }

    @objc func updateTimer() {
        if seconds < 1 {
            timer.invalidate()
            //Send alert to indicate "time's up!"
        } else {
            seconds -= 1
            timerLabel.text = timeString(time: TimeInterval(seconds))
        }
    }

    func timeString(time:TimeInterval) -> String {
        let hours = Int(time) / 3600
        let minutes = Int(time) / 60 % 60
        let seconds = Int(time) % 60
        return String(format:"%02i:%02i:%02i", hours, minutes, seconds)
    }

我想从中获取秒值modeLight并将其显示在timerLabel. 在第一个元素（例如5）将过期后，我想显示下一个等。怎么做？

标签： iosswift

Answer 1

您需要跟踪要使用的数组索引。

添加索引属性并初始化它

var modeLight = [5,30,60,30,60,30]
var timerIndex: Int 
var timer: Timer!

updateTimer()在你的函数中使用索引

func runTimer() {
    timerIndex = 0
    timer = Timer.scheduledTimer(timeInterval: 1, target: self, selector: (#selector(MasterViewController.updateTimer)), userInfo: nil, repeats: true)
}

@objc func updateTimer() {
    if seconds < 1 {
        timerIndex += 1
        if timerIndex >= modeLight.count { // to be safe
            endTimer()
            return
        }
        seconds = modeLight[timerIndex]
    } else {
        seconds -= 1
    }

    timerLabel.text = timeString(time: TimeInterval(seconds))
}

private func endTimer() {
    timer.invalidate()
    timerLabel.text = "00:00:00"
}