首页 > 解决方案 > c#中未知异常类型的泛型类

问题描述

在我的应用程序Web API中,我有一个异常过滤器,它假设捕获任何异常并将其传输到响应包装类中的客户端。我的目标是使该异常以正确的类型传输,以便客户端可以重建并重新抛出它。

以下是异常捕获器的代码:

public override void OnException(HttpActionExecutedContext actionExecutedContext)
    {

        HttpStatusCode OutputHttpCode = HttpStatusCode.InternalServerError;
        var exceptionType = actionExecutedContext.Exception.GetType();

        if (exceptionType == typeof(InvalidIDException))
        {
            OutputHttpCode = HttpStatusCode.Unauthorized;
        }

        //this way of getting type didnt work for me either
        //var exceptionType = typeof(RestErrorResponse<>).MakeGenericType(actionExecutedContext.Exception.GetType());

        actionExecutedContext.Response = new HttpResponseMessage()
        {
            Content = new StringContent(JsonConvert.SerializeObject(
                //this will not compile here, saying t is a variable but used like a type.
                //If i use generic "Exception" instead everything is working fine,
                //but it will be interpreted as generic exception on client side and
                //could not be handled properly if i rethrow it directly
                new RestErrorResponse<exceptionType> () //Exception will compile
                {
                    Content = null,
                    Status = RestStatus.Error,
                    Exception = actionExecutedContext.Exception
                }
                ),
                    System.Text.Encoding.UTF8, "application/json"),

            StatusCode = OutputHttpCode
        };

        base.OnException(actionExecutedContext);
    }

这是一个带有泛型的类,我试图将我的异常放入:

public class RestErrorResponse<E> :RestResponse<Object> {
    public E myException { get; set; }
}

如果我在“RestErrorResponse”类中使用通用异常,这是一个创建的 JSON:

{
  "Exception": {
    "ClassName": "InvalidLoginException",
    "Message": "Invalid User Name",
    "Data": {},
    "InnerException": null,
    "HelpURL": null,
    "StackTraceString": "....",
    "RemoteStackTraceString": null,
    "RemoteStackIndex": 0,
    "ExceptionMethod": "....",
    "HResult": -2147024809,
    "Source": "DB",
    "WatsonBuckets": null,
    "ParamName": null
  },
  "Status": {
    "Verbal": "Error",
    "Code": 1074
  },
  "Content": null
}

我的目标是获得:

{
  "InvalidLoginException": {
    "ClassName": "InvalidLoginException",
    "Message": "Invalid User Name",
    "Data": {},
    "InnerException": null,
    "HelpURL": null,
    "StackTraceString": "....",
    "RemoteStackTraceString": null,
    "RemoteStackIndex": 0,
    "ExceptionMethod": "....",
    "HResult": -2147024809,
    "Source": "DB",
    "WatsonBuckets": null,
    "ParamName": null
  },
  "Status": {
    "Verbal": "Error",
    "Code": 1074
  },
  "Content": null
}

标签: c#jsongenericsexceptionexception-handling

解决方案


RestErrorResponse 是您控制的类吗?如果是这样,它真的必须是通用的吗?考虑一下:

public class RestErrorResponse : RestResponse<Object> {
    public object Exception { get; set; }
}

现在您可以简单地实例化它:

var response = new RestErrorResponse 
{
     // other properties
     Exception = actionExecutedContext.Exception
}

如果无法更改,则需要反射来创建 RestErrorResponse 的实例。例如:

 var responseType = typeof(RestErrorResponse<>).MakeGenericType(exceptionType);
 dynamic response = Activator.CreateIntance(type);
 response.Content = null;
 response.Status = RestStatus.Error;
 response.Exception = actionExecutedContext.Exception;

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