pentaho - 将 PDI 响应转换为确定的结构
问题描述
我是 PDI 的新手,我正在从 API 中恢复信息,我需要转换特定结构的信息,我不清楚如何使用连接或其他转换来实现。
这是我的回答:
[
{
"457": {
"1": {
"value": "4.1",
"timestamp": 1534159593
},
"2": {
"value": "52.2",
"timestamp": 1534159593
},
"3": {
"value": "23.0",
"timestamp": 1534159593
},
"4": {
"value": "250.0",
"timestamp": 1534159593
}
}
}
]
我需要保留这种类型的东西,通过 POST 将其发送到另一个 API
{
"id": "457",
"type": "greenhouse",
"1": {
"value": 4.1,
"type": "Float",
"timestamp": 1534159593
},
"2": {
"value": 52.2,
"type": "Integer",
"timestamp": 1534159593
},
"3": {
"value": 23.0,
"type": "Integer",
"timestamp": 1534159593
},
"4": {
"value": 250.0,
"type": "Integer",
"timestamp": 1534159593
}
}
谢谢您的帮助。
编辑01
再次呼啦,
我按照你说的做,我有问题。
这是我的代码:
// Script here
var data = data2;
var tests = data;
var tests3 = {"457": {"2": {"value": "54.0", "timestamp": 1534246741}, "3": {"value": "22.2", "timestamp": 1534246741}, " 4 ": {" value ":" 260.0 "," timestamp ": 1534246741}," 21 ": {" value ":" 890.0 "," timestamp ": 1534246741}," 1 ": {" value ":" 4.13 "," timestamp ": 1534246741}," 17 ": {" value ":" 194.04687499999997 "," timestamp ": 1534246741}," 5 ": {" value ":" 35.417 "," timestamp ": 1534246741}," 6 ": {" value ":" 26.299999999999997 "," timestamp ": 1534246741}," 8 ": {" value ":" 4.7 "," timestamp ": 1534246741}," 15 ": {" value ":" 0.78 "," timestamp ": 1534246741}," 10 ": {" value ":" 24.94 "," timestamp ": 1534246741}," 22 ": {" value ":" 0.0 "," timestamp ": 1534246741}," 23 ": {" value ":" 0.0 "," timestamp ": 1534246741}," 24 ": {" value ":" 0.0 "," timestamp ": 1534246741}," 26 ": {" value ":" 0.0 "," timestamp ": 1534246741}," 653 ": {" value ":" 0.0 "," timestamp ": 1534246741}," 657 ": {" value ":" - 98.0 "," timestamp ": 1518420299}, "43": {"value": "11.892947103200001", "timestamp": 1534246741}, "42": {"value": "403.61749999999995", "timestamp": 1534246741}}};
var key = Object.keys (data) [0];
var finalobj = {};
for (var and in data [key]) {
finalobj [e] = {
type: "float"
, value: parseFloat (data [key] [e] .value)
, metadata: {
timestamp: {
value: parseInt (data [key] [e] .timestamp)
, type: "Integer"
}
}
};
}
var JsonOutput = JSON.stringify (finalobj);
变量data2是具有我的JSON的那个实际上是与tests3相同的信息,如果代码有效,但如果我一步将数据放入tests3,我不明白,因为数据具有相同的值并且必须工作并且JsonOutput 的响应是 {} 但如果它工作正常,我会使用 tests3 来执行此操作。
看起来它是在检索变量时,但随后我显示它具有数据和数据 2,并且与测试 3 的信息相同,我不明白会发生什么。
你能帮助我吗?
解决方案
现在还没有在 Pentaho 中编写嵌套 JSON 的内置步骤,您必须使用 JavaScript 来实现它,这里有一篇非常棒的帖子,我正在使用它作为构建自己的流程的指南。
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