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r - 以较粗的分辨率聚合栅格数据

问题描述

我有一个 0.25 * 0.25 度网格分辨率的数据集

lon <- c(-53.615449969, -53.365449969, -53.115449969, -53.365449969, 
     -53.115449969, -52.865449969, -53.365449969, -53.115449969, -52.865449969, 
     -52.615449969, -53.365449969, -53.115449969, -52.865449969, -52.615449969, 
     -52.365449969, -53.365449969, -53.115449969, -52.865449969, -52.615449969, 
     -52.365449969, -53.615449969, -53.365449969, -53.115449969, -52.865449969, 
     -52.615449969, -52.365449969, -52.115449969, -53.865449969, -53.615449969, 
     -53.365449969, -53.115449969, -52.865449969, -52.615449969, -52.365449969, 
     -52.115449969, -51.865449969, -54.365449969, -54.115449969, -53.865449969, 
     -53.615449969, -53.365449969, -53.115449969, -52.865449969, -52.615449969, 
     -52.365449969, -52.115449969, -51.865449969, -51.615449969, -54.615449969, 
     -54.365449969, -54.115449969, -53.865449969, -53.615449969, -53.365449969, 
     -53.115449969, -52.865449969, -52.615449969, -52.365449969, -52.115449969, 
     -51.615449969)


lat <- c(-33.627081271, -33.627081271, -33.627081271, -33.377081271, 
     -33.377081271, -33.377081271, -33.127081271, -33.127081271, -33.127081271, 
     -33.127081271, -32.877081271, -32.877081271, -32.877081271, -32.877081271, 
     -32.877081271, -32.627081271, -32.627081271, -32.627081271, -32.627081271, 
     -32.627081271, -32.377081271, -32.377081271, -32.377081271, -32.377081271, 
     -32.377081271, -32.377081271, -32.377081271, -32.127081271, -32.127081271, 
     -32.127081271, -32.127081271, -32.127081271, -32.127081271, -32.127081271, 
     -32.127081271, -32.127081271, -31.877081271, -31.877081271, -31.877081271, 
     -31.877081271, -31.877081271, -31.877081271, -31.877081271, -31.877081271, 
     -31.877081271, -31.877081271, -31.877081271, -31.877081271, -31.627081271, 
     -31.627081271, -31.627081271, -31.627081271, -31.627081271, -31.627081271, 
     -31.627081271, -31.627081271, -31.627081271, -31.627081271, -31.627081271, 
    -31.627081271)

 df <- as.data.frame(cbind(lon, lat))
 df$ID <- 1:nrow(df)
 coordinates(df) <- c(1,2)

 library(raster)
 elev <- getData('alt', country='BRA')

 plot(elev)
 plot(df, add = T)

在此处输入图像描述

对于每个 0.25 * 0.25 度的方格，我想计算平均海拔。我怎样才能在 R 中做到这一点？

标签： raggregationrastersp

解决方案

鉴于res(elev)是0.008333333（即1/120），您希望与因子 聚合.25 * 120 = 30。最简单的方法是

a <- aggregate(elev, 30, fun=mean, na.rm=TRUE)

现在分辨率是所需的，但不是与您指定的栅格对齐。插图：

r <- rasterFromXYZ(df)
s <- as(r, 'SpatialPolygons')
z <- crop(a, r, snap='out')
plot(z)
plot(s, add=TRUE)

相反，您可以这样做：

x <- resample(elev, r)

或（更精确，但更慢）

e <- extract(elev, s, fun=mean, na.rm=TRUE)
s$elev <- e

比较值

z <- rasterize(r, s)
plot(z, e)

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