首页 > 解决方案 > 无法将 PathFindExtensionW 输出分配给 WCHAR 数组

问题描述

我想将PathFindExtensionWapi 的输出分配给 WCHAR 数组。这个 api 返回一个 LPWSTR 指针。我搜索并发现将 LPWSTR 分配给 WCHAR 数组的方法如下:

WCHAR array[100] = PathFindExtensionW(,,,)

但这对我不起作用,我收到此错误:

表达式必须是可修改的左值

我正在使用 VS 2012。我的代码如下:

#include <windows.h>
#include <iostream>
#include "Shlwapi.h"

#pragma comment(lib,"shlwapi.lib")

void main(int argc, char *argv[]){

    int iToSizeB = 0;
    iToSizeB = MultiByteToWideChar(CP_UTF8, 0, argv[1], -1 , NULL, 0);

    WCHAR lpFileAddress[260] = {0};
    MultiByteToWideChar(CP_UTF8, 0, argv[1], -1, lpFileAddress, iToSizeB);

    WCHAR lpDotPosition[260] = {0};

    //this line must be correct but I receive error
    lpDotPosition = PathFindExtensionW(lpFileAddress);

    int iToSizeW = 0;
    iToSizeW = WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, NULL, 0, NULL, NULL);

    CHAR lpExtension[260] = {0};
    WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, lpExtension, iToSizeW, NULL, NULL);

    printf("the format is:\n");
    printf(lpExtension);
    printf("\n");

    getchar();
}

这有什么问题?

感谢您的解决方案。

标签: cwinapivisual-studio-2012console-application

解决方案


您不能通过为数组分配指针来填充数组。您必须复制数据,例如使用lstrcpynW()或类似功能:

LPCWSTR lpDotPosition = PathFindExtensionW(lpFileAddress);

WCHAR lpExtensionW[MAX_PATH] = {0};
lstrncpy(lpExtensionW, lpDotPosition, MAX_PATH);

但是,PathFindExtension()只需在您传入的字符串缓冲区内返回一个指针,因此无需分配扩展的单独副本,数据已经预先分配,并且返回的指针将在输入期间保持有效字符串有效:

#include <windows.h>
#include <iostream>
#include <Shlwapi.h>
#pragma comment(lib, "shlwapi.lib")

int main(int argc, char *argv[])
{
    WCHAR lpFileAddress[MAX_PATH] = {0};
    int iToSizeB = MultiByteToWideChar(CP_UTF8, 0, argv[1], -1, lpFileAddress, MAX_PATH);

    LPCWSTR lpDotPosition = PathFindExtensionW(lpFileAddress);

    CHAR lpExtension[MAX_PATH] = {0};
    int iToSizeW = WideCharToMultiByte(CP_UTF8, 0, lpDotPosition, -1, lpExtension, MAX_PATH, NULL, NULL);

    printf("the format is:\n%s\n", lpExtension);

    getchar();
    return 0;
}

另一方面,不需要使用MultiByteToWideChar()andWideCharToMultiByte()只是为了搜索一个char字符串,你可以使用PathFindExtensionA()

#include <windows.h>
#include <iostream>
#include <Shlwapi.h>
#pragma comment(lib, "shlwapi.lib")

int main(int argc, char *argv[])
{
    LPCSTR lpExtension = PathFindExtensionA(argv[1]);

    printf("the format is:\n%s\n", lpExtension);

    getchar();
    return 0;
}

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