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python - python如果多个字符串返回句子中包含的单词

问题描述

我有一个单词列表，我想做 if 语句，下面是我的列表：

list = ['camera','display','price','memory'(will have 200+ words in the list)]

这是我的代码：

def check_it(sentences):
    if 'camera' in sentences and 'display' in sentences and 'price' in sentences:
        return "Camera/Display/Price"
    if 'camera' in sentences and 'display' in sentences:
        return "Camera/Display"
    ...
    return "Others"

h.loc[:, 'Category'] = h.Mention.apply(check_it)

这些组合会太多，而且我想让单词单独返回到行。有谁知道如何制作这个样本并单独返回单词而不是“相机/显示器/价格”？

标签： pythonpandascombinationsmatching

解决方案

由正则表达式使用str.findall- 将列表的所有值与|，最后一个str.join值连接/：

df = pd.DataFrame({'Mention':['camera in sentences and display in sentences',
                              'camera in sentences price']})


L = ['camera','display','price','memory']
pat = '|'.join(r"\b{}\b".format(x) for x in L)
df['Category'] = df['Mention'].str.findall(pat).str.join('/')
print (df)
                                        Mention        Category
0  camera in sentences and display in sentences  camera/display
1                     camera in sentences price    camera/price

另一个具有列表理解的解决方案，也用于列表使用生成器join：

df['Category1'] = [[y for y in x.split() if y in L] for x in df['Mention']]
df['Category2'] = ['/'.join(y for y in x.split() if y in L) for x in df['Mention']]
print (df)
                                        Mention          Category1  \
0  camera in sentences and display in sentences  [camera, display]   
1                     camera in sentences price    [camera, price]   

        Category2  
0  camera/display  
1    camera/price

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