java - Java中的while循环

Question

我试图通过将句子分成单个单词来制作单词计数器。我尝试通过使用 split 方法（对于对象字符串）来完成此操作。但是，我无法计算单词，因为循环在中途终止。你能帮助我吗？

期望：找出字符串中的单词重复了多少次。

public static void main(String[] args) {
    int count = 0, i=0;
    int max,a;
    ArrayList<Integer> lastCount = new ArrayList<Integer>();
    String yazi ="How ı can do that? I don't know. Can you help me? I need help for counter. Thanks in advance for all.";
    String yazi1 = yazi.replace(",","");
    yazi1 = yazi1.replace(".", "");
    yazi1 = yazi1.replace("?", "");
    yazi1 = yazi1.replace("!", "");
    yazi1 = yazi1.toLowerCase();
    yazi1 = yazi1.replace("ı", "i");
    String[] words = yazi1.split(" ");
    for(a=0; a < words.length; a++) {
        while(i<words.length){
            if(words[a].equals(words[i])) {
                max = 0;
                lastCount.add(a, max+1);
            }
            i++;
        } 
        System.out.println(a+1 +". Word: " + words[a] + " || Counter: "+lastCount.get(a));
    }
} 

标签： javaloopswhile-loopcounter

Answer 1

首先，你应该初始化maxand a; 它消除了混乱并使其更易于阅读。其次，您应该使用嵌套的 for 循环而不是 for 循环和 while 循环。第三，我相信一旦i到达words.length，您不会将其重置回 0。当a为 0 时，i转到words.length，并且迭代 1 完成。a变为 1，但i仍然是words.length，所以什么也没有发生。如此重复直到a变为words.length，程序停止。几乎什么都没有完成。我相信这个问题可以通过制作只存在于 for 循环中a的i局部变量来解决。代码应变为：

public static void main(String[] args) {
int count = 0;
int max = 0;
ArrayList<Integer> lastCount = new ArrayList<Integer>();
String yazi ="How ı can do that? I don't know. Can you help me? I need help for counter. Thanks in advance for all.";
String yazi1 = yazi.replace(",","");
yazi1 = yazi1.replace(".", "");
yazi1 = yazi1.replace("?", "");
yazi1 = yazi1.replace("!", "");
yazi1 = yazi1.toLowerCase();
yazi1 = yazi1.replace("ı", "i");
String[] words = yazi1.split(" ");
for(int a=0; a < words.length; a++) {
    for(int i=0; i < words.length; i++){
        if(words[a].equals(words[i])) {
            max = 0;
            lastCount.add(a, max+1);
        }
    } 
    System.out.println(a+1 +". Word: " + words[a] + " || Counter: "+lastCount.get(a));
}

}