首页 > 解决方案 > 第二次运行时出错

问题描述

程序第一次运行完美,但第二次没有输入用户的字符串,我不知道为什么?

我认为存在问题,getline(cin,str);但我无法解决问题

#include<iostream>
#include<string>

using namespace std;

int main(){
    string str;
    char check;
    do{
        system("cls");
        cout<<"Enter the number (sample : +92121234567(Must contain 12 characters)) : ";
        getline(cin,str);
        cout<<endl<<str;
    if(str.length() == 12){

        string countrycode = str.substr(0,3);

        if(countrycode == "+92"){

            string citycode = str.substr(3,2);

            if(citycode == "51"){
                cout<<endl<<"This number belongs to Islamabad";
            }else if(citycode == "42"){
                cout<<endl<<"This number belongs to Lahore";
            }else if(citycode == "21"){
                cout<<endl<<"This number belongs to Karachi";
            }else{
                cout<<endl<<"Unknown Number";
                cout<<endl<<"Remarks : ";
                cout<<endl<<"Unknown city code";
            }
        }else{
            if(str.substr(0,1) =="-"){
                cout<<endl<<"Unknown Number";
                cout<<endl<<"Remarks : ";
                cout<<endl<<"Wrong country code format";    
            }
            if(str.substr(1,2) !="92"){
                cout<<endl<<"Unknown Number";
                cout<<endl<<"Remarks : ";
                cout<<endl<<"Unknown country code"; 
            }   
        }
    }else{
        cout<<endl<<"Unknown Number";
        cout<<endl<<"Remarks : ";
        cout<<endl<<"Number is over 12 characters";
    }


    cout<<endl<<"Do you want to enter another number (y/n): ";
    cin>>check;
    //str.clear();
}while(check=='y'||check=='Y');

cout<<endl<<"End of Program. Bye!"<<endl;
system("pause");
return 0;

}

标签: c++string

解决方案


使用 cin >> str; 不知道为什么,但 getline 也不适合我。


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