python - 将 2d dict 的 dict 中的值除以与该键匹配的另一个 dicts 值

Question

这些字典很长，我需要遍历多个键值。举一个简短的例子。从长远来看，我需要将所有数字除以适当的计数以获得平均值。

counts = {'A':10, 'B':14}
totals = {'A':{'atk':20,'str':20,'def':20}, 
          'B':{'atk':140,'str':140,'def':140}}

我需要更新总数，以便最终

totals = {'A':{'atk':2,'str':2,'def':2}, 
          'B'{'atk':10, 'str':10,'def':10}}

标签： pythonpython-3.xdictionary

Answer 1

我会使用O(1)dict 查找进行 dict 理解

>>> {k1: {k2: v/counts[k1]  for k2, v in d.items()} for k1, d in totals.items() }

{'A': {'atk': 2.0, 'str': 2.0, 'def': 2.0},
 'B': {'atk': 10.0, 'str': 10.0, 'def': 10.0}}

---

总能扩大领悟。。

f = {}
for k1, d in totals.items():
    sub = {}
    for k2, v in d.items():
        sub[k2] = v/counts[k1]
    f[k1] = sub