首页 > 解决方案 > 如何加快条件MYSQL查询

问题描述

查询是:

SELECT RP.pID
  , (IF(RI.p01 = 54, 1, 0)
     + IF(RI.p02 = 16, 1, 0)
     + IF(RI.p03 = 54, 1, 0)
     + IF(RI.p04 = 92, 1, 0)
     + IF(RI.p05 = 34, 1, 0)
     + IF(RI.p06 = 51, 1, 0)
     + IF(RI.p07 = 62, 1, 0)
     + IF(RI.p08 = 98, 1, 0)
     + IF(RI.p09 = 14, 1, 0)
     + IF(RI.p10 = 25, 1, 0)
     + IF(RI.p11 = 34, 1, 0)
     + IF(RI.p12 = 67, 1, 0)
     + IF(RI.p13 = 81, 1, 0)
     + IF(RI.p14 = 29, 1, 0)
     + IF(RI.p15 = 24, 1, 0)
     + IF(RI.p16 = 45, 1, 0)
     + IF(RI.p17 = 72, 1, 0)
     + IF(RI.p18 = 86, 1, 0)
     + IF(RI.p19 = 25, 1, 0)
     + IF(RI.p20 = 95, 1, 0)
     + IF(RI.p21 = 92, 1, 0)
     + IF(RI.p22 = 31, 1, 0)
     + IF(RI.p23 = 24, 1, 0)
     + IF(RI.p24 = 78, 1, 0)) AS ATTP
FROM RP
LEFT JOIN RI
    ON RP.rID = RI.rID
    AND RP.nID = '1'
WHERE RI.p25 > ((RI.p27 + RI.p26) * 8)
ORDER BY ATTP DESC LIMIT 1000000;

在实际情况下,有 27 个这样的 if,查询需要 25-35 秒才能完成。

我在其中检查这些条件的表是相关的,并且每天都会增加约 50 000 条记录。

为了加快查询的 WHERE 部分,我在 iNR 上有主索引,但是如何加速这些 IFS?

执行计划:

在此处输入图像描述

表结构:

CREATE TABLE `RI` (
  `rID` mediumint(5) unsigned NOT NULL AUTO_INCREMENT,
  `p01` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p02` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p03` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p04` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p05` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p06` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p07` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p08` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p09` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p10` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p11` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p12` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p13` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p14` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p15` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p16` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p17` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p18` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p19` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p20` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p21` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p22` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p23` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p24` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p25` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p26` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `p27` tinyint(3) unsigned NOT NULL DEFAULT '0',
  `ils` mediumblob NOT NULL,
  PRIMARY KEY (`rID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_lithuanian_ci;

CREATE TABLE `RP` (
  `pID` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
  `rID` mediumint(8) unsigned NOT NULL,
  `nID` mediumint(8) unsigned NOT NULL,
  PRIMARY KEY (`pID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_lithuanian_ci;

标签: mysql

解决方案


修复 1:索引所有 4 列 a、b、c 和 d 将有助于更快地处理。

修复 2:可能会添加一个触发器,在插入或更新值时更新同一表中的另一列将解决问题。

两个修复都是临时的,请提供有关问题陈述的更多信息,说明您为什么需要查询中的 if 希望对您有所帮助


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