javascript - 有没有办法将 reduce 应用于两个数组但不重置调用之间的累加器？

Question

所以如果我有一个对象数组：

var synched = [{
   name = "something",
   value = 11132
}, {
   name = "something else",
   value = 1231233
}...]

和另一个几乎相同但包含其他一些值的数组：

var opened = [{
   name = "something",
   value = 1233312
}, {
   name = "something else",
   value = 12312333
}, {
   name = "something",
   value = 1241233

}]

我想将它们全部加入到一个对象数组中，在其中计算任一数组中“名称”的准确度总数。

var result = [{
    name: "something",
    opened: 2,
    synched: 1,
    total: 3
}, {
    name: "something else",
    opened: 1,
    synched: 1,
    total: 2
}]

有没有比多次array.reduce调用更有效的方法呢？

var data = synched.reduce(function (data, item) {
    var key = item.name
    var created = (data[key] || (data[key] = {'name': key, 'opened': 0, 'synched': 0, 'total': 0}));
    created['synched'] += 1;
    created['total'] += 1;

    return data;
}, {});

var data1 = opened.reduce(function (data1, item) {
    var key = item.name
    var created = (data1[key] || (data1[key] = {'name': key, 'opened': 0, 'synched': 0, 'total': 0}));
    created['opened'] += 1;
    created['total'] += 1;

    return data1;
}, {});

Object.keys(data).forEach(function (key) {
    if(data1.hasOwnProperty(key)){
        data1[key]['synched'] = data[key]['synched'];
        data1[key]['total'] = data[key]['total'] + data1[key]['total'];
    } else {
        data1[key] = data[key];
    }
});

var result = Object.keys(data1).map(function(item) { return data1[item]; });

编辑：

按照@Pointy 的建议，我可以这样做：

var data1 = opened.reduce(function (data, item) {
        var key = item.name
        var created = (data[key] || (data[key] = {'name': key, 'opened': 0, 'synched': 0, 'total': 0}));
        created['opened'] += 1;
        created['total'] += 1;

        return data;
    }, data);

这将使我摆脱第三次迭代。谢谢！

标签： javascriptarraysperformance