javascript - 使用 getLinkUrl(offset) 的 Google Apps 脚本问题

Question

我试图弄清楚如何getLinkUrl(offset)在 Google Apps Script 中使用。

我在这里找到了参考 - http://googlescriptreference.com/Document/Text/getlinkurloffset/，但我在网上找不到任何示例。

此 GASParagraph在日志中返回

var paragraph = tableCell.getChild(0);

此 GASthe text string in the paragraph在日志中返回

var paragraphText = paragraph.getText();

此 GASNULL在日志中返回

var paragraphText = paragraph.getLinkUrl();

此 GAS 返回错误（找不到方法 getLinkUrl(number)。）并且日志中没有任何内容

var paragraphText = paragraph.getLinkUrl(2);

有人可以帮我了解如何使用getLinkUrl(offset)吗？

谢谢你的帮助！

标签： javascriptgoogle-apps-scriptgoogle-docs

Answer 1

我试图getLinkUrl(offset)直接在段落元素上使用（不是工作示例），但我需要使用asText()之前的方法getLinkUrl(offset)。

不工作

var paragraphText = paragraph.getLinkUrl(2);

在职的

var paragraphText = paragraph.asText().getLinkUrl(2);

谷歌文档 https://docs.google.com/document/d/136G549zIYPYBndXs70ZnR_wEFg5fPST9ZGsOlTgmDyM/edit

//Works if link is on a word or words instead of entire paragraph

function myFunctionP1() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(2); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.asText().getLinkUrl(2); //paragraph text
  Logger.log(paragraphText)


}



//Works if link is on entire paragraph
//Works if link is on entire paragraph
//Works if link is on entire paragraph
function myFunctionP2() {
  //Find out how many Children there are
  var body = DocumentApp.getActiveDocument().getBody();
  Logger.log(body.getNumChildren());

  //Find out which child is table
  var table = body.getChild(4); //table is child#2
  Logger.log(table);

  //Find tableCell inside of table
  var tableCell = table.getChild(0).getChild(0); //tableCell
  Logger.log(tableCell)

  //Find paragraph inside of tableCell 
  //I think, but I'm not sure, the HYPERLINK will be found somewhere within the PARAGRAPH element. But I can't figure out how to get to it.
  var paragraph = tableCell.getChild(0); //paragraph element
  Logger.log(paragraph)

  //Get paragraph text 
  var paragraphText = paragraph.getText(); //paragraph text
  Logger.log(paragraphText)

  //Get HYPERLIINK from paragraph text 
  var paragraphHYPERLINK = paragraph.getLinkUrl(); //paragraph text
  Logger.log(paragraphHYPERLINK)  

}

@Tanaike 帮助我找到了这个解决方案。 https://stackoverflow.com/users/7108653/tanaike