java - 从java数组中获取五个随机元素

问题描述

我已经在这个项目上工作了几天，我能够完成大部分工作，但我一直在努力从我的阵列中取出五个不同的项目。我可以选择五次相同的项目。

这是我的代码的样子：

public class CardGuessingGame {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {

        String[] myCards = new String[]{"two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "jack", "queen", "king", "ace"}; // Array for cards

        Random rand = new Random(); //random construction
        rand.nextInt(13); // Sets rand to 0-12 int
        //int randomNums = rand.nextInt(13); // sets randNums from 0-12
        int randomNums = rand.nextInt(myCards.length); //Randomizes "randomNums to the length of the array"
        String cardInHand = myCards[(int)randomNums];

        for (randomNums=0; randomNums < 5; randomNums++) {

            System.out.println(cardInHand);
        }

        System.out.print("Guess the card in my hand: "); // Prints to user asking for guess

        Scanner answer = new Scanner(System.in); // gets user input
        String s = answer.nextLine(); //stores user input inside variable s

        if(s.equals(cardInHand)) {

            System.out.println("I do have that card in hand");
        } else {

            System.out.println("I do not have that card in hand!");
        }

        System.out.print("These were the cards I had in hand: ");
        System.out.println(cardInHand);
    }
}

这是输出

run:
four
four
four
four
four
Guess the card in my hand: four
I do have that card in hand
These were the cards I had in hand: four

我现在所拥有的工作，但不正确。

标签： javaarraysrandom

在阅读源代码时，我编写了新代码来增加您的歧义。因此，我在某些行中添加了注释以清楚地理解。

public class CardGuessingGame  {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {


        //list of cards
        List<String> myCards = Arrays.asList("two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "jack", "queen", "king", "ace");
        //shuffle cards
        Collections.shuffle(myCards);

        //get first 5 elements from shuffled list
        HashSet<String> myHand = new HashSet<>();
        for (int i = 0; i < 5; i++) {
            myHand.add(myCards.get(i));
            System.out.println(myCards.get(i));
        }

        System.out.print("Guess the card in my hand: "); // Prints to user asking for guess

        Scanner answer = new Scanner(System.in); // gets user input
        String s = answer.nextLine(); //stores user input inside variable s

        //if set contains , you found the card
        if (myHand.contains(s)) {
            System.out.println("I have that card in my hand");
        } else {
            System.out.println("I do not have that card in hand!");
        }

        System.out.print("These are the cards which is in my hand: ");
        //write all cards in my hand with sepearete comma
        System.out.println(String.join(",", myHand));
    }
}

java - 从java数组中获取五个随机元素

问题描述

解决方案

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