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php - PHP WebSocket 服务器无法访问 Origin 和 Referrer 标头

问题描述

我有一个简单的 PHP websocket 服务器

这是完整的代码：https ://gist.github.com/hack4mer/e40094001d16c75fe5ae8347ebffccb7

while (true) {

$changed = $clients;
socket_select($changed, $null, $null, 0, 10);

//check for new socket
if (in_array($socket, $changed)) {
    $socket_new = socket_accept($socket); //accpet new socket
    $clients[] = $socket_new; //add socket to client array

   //THIS DOES NOT WORK
   print_r($_SERVER);
   die();

}

在浏览器的网络选项卡中，我可以确认以下请求：

Request URL: ws://localhost:12345/
Provisional headers are shown
Accept-Encoding: gzip, deflate, br
Accept-Language: en-US,en;q=0.9,hi;q=0.8,ms;q=0.7
Cache-Control: no-cache
Connection: Upgrade
Host: localhost:12345
Origin: http://localhost

但是我无法在我的脚本中访问这些请求标头。

我的目标是将 WebSocket 的访问限制在少数主机上

标签： phpapachephp-socket

解决方案

我通过在握手之前进行标头检查解决了这个问题。

完整代码：https ://gist.github.com/hack4mer/e40094001d16c75fe5ae8347ebffccb7

function perform_handshaking($receved_header,$client_conn, $host, $port)
{
$headers = array();
$lines = preg_split("/\r\n/", $receved_header);
foreach($lines as $line)
{
    $line = chop($line);
    if(preg_match('/\A(\S+): (.*)\z/', $line, $matches))
    {
        $headers[$matches[1]] = $matches[2];
    }
}

 //HEADERS AVAILABLE HERE -> $headers

$secKey = $headers['Sec-WebSocket-Key'];
$secAccept = base64_encode(pack('H*', sha1($secKey . '258EAFA5-E914-47DA-95CA-C5AB0DC85B11')));
//hand shaking header
$upgrade  = "HTTP/1.1 101 Web Socket Protocol Handshake\r\n" .
"Upgrade: websocket\r\n" .
"Connection: Upgrade\r\n" .
"WebSocket-Origin: $host\r\n" .
"WebSocket-Location: ws://$host:$port/demo/shout.php\r\n".
"Sec-WebSocket-Accept:$secAccept\r\n\r\n";
socket_write($client_conn,$upgrade,strlen($upgrade));
}

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