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问题描述

我想补充一点,只要它识别出“搜索 X”,它就会搜索“X”,但我不知道如何将其添加到语法中,或者如何用我的开关做这样的事情陈述。

private void Form1_Load(object sender, EventArgs e)
{
    Choices commands = new Choices();
    commands.Add(new string[] { "hello", "start chrome", "search" });
    GrammarBuilder gBuilder = new GrammarBuilder();
    gBuilder.Append(commands);
    gBuilder.Culture = new System.Globalization.CultureInfo("en-GB");
    Grammar grammar = new Grammar(gBuilder);

    recEngine.LoadGrammarAsync(grammar);
    recEngine.SetInputToDefaultAudioDevice();
    recEngine.SpeechRecognized += RecEngine_SpeechRecognized;
}

private void RecEngine_SpeechRecognized(object sender, SpeechRecognizedEventArgs e)
{
    switch (e.Result.Text)
    {
        case "hello":
            synthesizer.SpeakAsync("Hello! How are you doing today?");
            break;
        case "start chrome":
            Process.Start("http://www.google.com");
            break;
        case "search":
            SearchChrome("search");
            break;
    }
}

static void SearchChrome(string searchterm)
{
    Process.Start("https://www.google.com/search?q=" + searchterm);
}

所以我想添加到我的语法“Search X”和我的案例“Search X”中,它会搜索 X 是什么。

提前致谢!

标签: c#switch-statementspeech-recognitionwildcard

解决方案


你必须做一个更复杂的语法。您选择的语法规则类型是选择一。它并不完全适合您想要捕获关键字后面的内容。要捕获以下内容,您必须使用 SemanticResultKey 规则。这里解释:https ://docs.microsoft.com/en-us/dotnet/api/system.speech.recognition.semanticresultkey?view=netframework-4.7.2

该示例与您想要的完全匹配:它从表达式“我的密码是.....”中提取密码


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