首页 > 解决方案 > MySQL 每 15 分钟计算一次平均值

问题描述

嗨,我有一张像这样的桌子:

CREATE TABLE `data` (
 `time` DATETIME NOT NULL.
 `cpu` DECIMAL(10, 4) UNSIGNED NOT NULL
)

我每 10 秒排一次,例如:

time                    cpu     
2018-09-12 11:49:41     0.200
2018-09-12 11:49:51     0.100
2018-09-12 11:50:01     0.200
2018-09-12 11:50:11     0.301
2018-09-12 11:50:21     0.100
2018-09-12 11:50:31     0.000
2018-09-12 11:50:41     0.200
2018-09-12 11:50:51     0.100
2018-09-12 11:51:01     0.100
2018-09-12 11:51:11     0.400
2018-09-12 11:51:21     0.000
2018-09-12 11:51:31     0.000
2018-09-12 11:51:41     0.300
2018-09-12 11:51:51     0.300
2018-09-12 11:52:01     0.300
2018-09-12 11:52:11     0.200
2018-09-12 11:52:21     0.000
2018-09-12 11:52:31     0.200
2018-09-12 11:52:41     0.100
2018-09-12 11:52:51     0.200
2018-09-12 11:53:01     0.801
2018-09-12 11:53:11     0.100
2018-09-12 11:53:21     0.200
2018-09-12 11:53:31     0.200
2018-09-12 11:53:41     0.100

我想每 15 分钟计算一次 CPU 平均值。我该怎么做?

提前致谢!!!

我在用着:

MariaDB [(none)]> SELECT VERSION();
+----------------------------------+
| VERSION()                        |
+----------------------------------+
| 10.1.30-MariaDB-0ubuntu0.17.10.1 |
+----------------------------------+
1 row in set (0.00 sec)

标签: sqldatedatetimegroup-bymariadb

解决方案


您可以将 15 分钟的边界截断time(将秒数归零,减去分钟 mod 15 分钟),然后按结果值分组:

SELECT clamped_time, AVG(cpu) AS average_cpu
FROM (
    SELECT
        time
        - INTERVAL EXTRACT(SECOND FROM time) SECOND
        - INTERVAL EXTRACT(MINUTE FROM time) % 15 MINUTE AS clamped_time,
        cpu
    FROM data
) AS sq
GROUP BY clamped_time

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