首页 > 解决方案 > PHP sqlserv - 执行存储过程的问题

问题描述

我正在尝试将参数传递给存储过程存储过程在管理工作室中执行良好,但是在尝试了下面代码的许多变体之后。

返回错误:

FAILED!Array ( [0] => Array ( [0] => IMSSP [SQLSTATE] => IMSSP [1] => -14 [code] => -14 [2] => 传递给 sqlsrv_execute 的参数无效。 [消息] => 向 sqlsrv_execute 传递了一个无效参数。))

<?php
include("connection.php");

$clerk_name1 = ''; $clerk_name2 = ''; $order1 = ''; $order2 = ''; $part1 = ''; $part2 = ''; $customer1 = ''; $customer2 = ''; $date_from = ''; $date_to = '';  

if (!empty($_REQUEST['clerk_name1']) && !empty($_REQUEST['clerk_name2']) && !empty($_REQUEST['order1']) && !empty($_REQUEST['order2']) && !empty($_REQUEST['part1']) && !empty($_REQUEST['part2']) && !empty($_REQUEST['customer1']) && !empty($_REQUEST['customer2']) && !empty($_REQUEST['date_from']) && !empty($_REQUEST['date_to']))

$sql = "SET NOCOUNT ON; {CALL sp_order_activities (@clerk_name1 = ?, @clerk_name2 = ?, @order1 = ?, @order2  = ?, @part1 = ?, @part2 = ?, @customer1 = ?, @customer2 = ?, @date_from = ?, @date_to = ?)}";

$clerk_name1 = $_GET['clerk_name1']; $clerk_name2 = $_GET['clerk_name2']; $order1 = $_GET['order1'];
$order2 = $_GET['order2'];$part1 = $_GET['part1'];
$part2 = $_GET['part2']; $customer1 = $_GET['customer1'];
$customer2 = $_GET['customer2'];$date_from = $_GET['date_from'];
$date_to = $_GET['date_to'];

$stmt = sqlsrv_prepare( $conn, $sql, [
    [$clerk_name1, SQLSRV_PARAM_IN],
    [$clerk_name2, SQLSRV_PARAM_IN],
    [$order1, SQLSRV_PARAM_IN],
    [$order2, SQLSRV_PARAM_IN],
    [$part1, SQLSRV_PARAM_IN],
    [$part2, SQLSRV_PARAM_IN],
    [$customer1, SQLSRV_PARAM_IN],
    [$customer2, SQLSRV_PARAM_IN],
    [$date_from, SQLSRV_PARAM_IN],
    [$date_to, SQLSRV_PARAM_IN]
]);
if (!sqlsrv_execute($stmt)) {
    echo "execute FAILED!";
    die(print_r(sqlsrv_errors(), true));
}
$data = [];
while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ){

	$data[] = $row;
	
}

echo json_encode($data);
ob_flush();
flush();
?>

标签: phpsqlsql-serverstored-proceduressqlsrv

解决方案


推荐阅读