python - 访问基类变量

Question

如何id从我的孩子班级访问？

class BaseClass:
    id = 'testing'

class MyClass(BaseClass):
    something = id

更具体地说，我无法id访问class:User：

class BaseModel:
    id = db.Column(db.Integer, primary_key=True)

class User(db.Model, BaseModel):
    username = db.Column(db.String(35), nullable=False, unique=True)

    followed = db.relationship(
        'User',
        secondary=followers,
        primaryjoin=(followers.c.follower_id == id),
        secondaryjoin=(followers.c.followed_id == id),
        backref=db.backref('followers', lazy='dynamic'),
        lazy='dynamic')

标签： pythonsqlalchemyflask-sqlalchemy

Answer 1

这是一个在示例示例中测试继承的小程序：

class BaseClass:
    id = 'testing'

class MyClass(BaseClass):
    something = BaseClass.id

if __name__ == '__main__':
    print(MyClass().something) # >> "testing"

您应该可以替换id为BaseModel.id. 如果没有，请报告您遇到的错误。