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c# - C# 将 1D 数组拆分为每 N 个值的 2D 数组

问题描述

我有一个一维整数数组：

int[] array = { 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32,33, 34,40,41,42,43, 44};

我想将此一维数组划分为 4 行 5 列的 2D 数组，其中前 5 个值进入第 1 行，接下来的 5 个值进入第 2 行，依此类推。最终结果应如下所示：

数组2D：

[[10, 11, 12, 13, 14]
[20, 21, 22, 23, 24]
[30, 31, 32, 33, 34]
[40, 41, 42, 43, 44]]

实际上，数组会更长（可能超过 100 行），但列数为 5，行数可被 5 整除。例如，我已经简化了。这是我到目前为止所尝试的：

int[] array = { 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32,33, 34,40,41,42,43, 44};
int[,] array2D = new int[(array.Length/5),5];

int count_0 = 1;
int count_1 = 1;
int count_2 = 1;
int count_3 = 1;
int count_4 = 1;

for (int i = 0; i < array.Length; i++)
{
    if (i < 5)
    {
        // works for the first 5 values: 
        array2D[0, i] = array[i];
    }
    // I tried this approach for the rest where I try to say that if Im at index 5, 
    //and every 5th element from here, append to it to index[i,0] of array2D and so on. 
    // This do not work, and is what I need help with.
    else if (i >= 5 && i % 5 == 0)
    {
        array2D[count_0, 0] = array[i];
        count_0++;
    }
    else if (i >= 6 && i % 5 == 0)
    {
        array2D[count_1, 1] = array[i];
        count_1++;
    }

    else if (i >= 7 && i % 5 == 0)
    {
        array2D[count_2, 2] = array[i];
        count_2++;
    }

    else if (i >= 8 && i % 5 == 0)
    {
        array2D[count_3, 3] = array[i];
        count_3++;
    }
    else if (i >= 9 && i % 5 == 0)
    {
        array2D[count_4, 4] = array[i];
        count_4++;
    }
}

当然，对于这个例子，我可以说if > 5 && <10 {append to array2D}等等if > 10 && <15 {append to array2D}，但我想要一些适用于数百个值的大型数组的东西。如果有人有更聪明的方法来做到这一点，请告诉我。

感谢您的任何帮助！

标签： c#arrays.netwinforms

解决方案

您可以只计算索引：

for(int i=0;i<array.Length;i++)
    array2D[i/5, i%5] = array[i];

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