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javascript - 如何避免跳过第二个数组中的数组索引？

问题描述

怎么才能不跳过当年数组的元素呢？

我希望结果是：

Banana
0
Mango
1

当前结果：

Banana
0
Mango
3

代码在这里：

<body>
<p id="demo"></p>
<script>
    var fruits, text, year, i;
    fruits = ["Banana", "Orange", "Apple", "Mango"];
    year = ["0", "1", "2", "3"];
    text = "<ul>";
    for (i = 0; i < fruits.length; i++) {
        switch (fruits[i]) {
            case 'Mango':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Pine apple':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Grape':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Banana':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
        }
    }
    text += "</ul>";
    document.getElementById("demo").innerHTML = text;
</script>

标签： javascriptarraysloopsswitch-statement

解决方案

像您一样循环遍历数组，并在水果与其中一个 case 语句匹配时增加第二个计数器。使用计数器从数组中获取年份编号：

var fruits, text, year, i;
fruits = ["Banana", "Orange", "Apple", "Mango"];
year = ["0", "1", "2", "3"];
text = "<ul>";
let counter = 0; // <-- define a second counter
for (i = 0; i < fruits.length; i++) {
  switch (fruits[i]) {
    case 'Mango':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++; // <-- that only get's incremented when a case is matched
      break;
    case 'Pine apple':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Grape':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Banana':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
  }
}
text += "</ul>";
document.getElementById("demo").innerHTML = text;
<p id="demo"></p>

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