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sql - 明天的第一个值出现在今天行的最后一个单元格上

问题描述

感谢大家对 Stack 的支持，我离解决问题越来越近了。但是我对 SQL 中枢轴的日期和时间有疑问。

我有以下查询：

DECLARE @_SerialNumber NVARCHAR(MAX)        
DECLARE @_DateFrom DATETIME
DECLARE @_DateTo DATETIME


SET @_SerialNumber = '2209'
SET @_DateFrom = '2018-09-20 00:00'
SET @_DateTo = DATEADD(DD, 1, @_DateFrom)

SELECT [Serial], 
       [Channel],
       [ReadingDate],
       [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],[02:15],[02:30],[02:45],[03:00],
       [03:15],[03:30],[03:45],[04:00],[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
       [06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],[08:15],[08:30],[08:45],[09:00],
       [09:15],[09:30],[09:45],[10:00],[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
       [12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],[14:15],[14:30],[14:45],[15:00],
       [15:15],[15:30],[15:45],[16:00],[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
       [18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],[20:15],[20:30],[20:45],[21:00],
       [21:15],[21:30],[21:45],[22:00],[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00]
--INTO [Staging].[PivotedData]
FROM(
    SELECT 
        SerialNumber AS [Serial],
        ChannelName AS [Channel],
        CAST(ReadingDate AS DATE) AS [ReadingDate],
        CAST(ReadingDate AS TIME(0)) AS [ReadingTime],
        ChannelValue AS [Value]
    FROM [Staging].[UriData]
    WHERE
        ChannelName IN (SELECT ChannelName FROM Staging.ActiveChannels )
        AND ReadingDate > @_DateFrom AND  ReadingDate <= @_DateTo
        AND SerialNumber = @_SerialNumber
        AND Processed = 0
        AND ChannelName = 'm1'
    ) AS [Raw]
PIVOT
(
    MAX( [Value] ) FOR [ReadingTime] IN( [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],
                                         [02:15],[02:30],[02:45],[03:00],[03:15],[03:30],[03:45],[04:00],
                                         [04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
                                         [06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],
                                         [08:15],[08:30],[08:45],[09:00],[09:15],[09:30],[09:45],[10:00],
                                         [10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
                                         [12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],
                                         [14:15],[14:30],[14:45],[15:00],[15:15],[15:30],[15:45],[16:00],
                                         [16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
                                         [18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],
                                         [20:15],[20:30],[20:45],[21:00],[21:15],[21:30],[21:45],[22:00],
                                         [22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00])
) AS pvt

ORDER BY ReadingDate DESC, Channel, [Serial]

该查询产生以下结果：

-----------------------------------------------------------------------------------------------------------------------------
Serial | Channel | ReadingDate | 00:15 | 00:30 | 00:45 | 01:00 | 01:15  <--- ReadingTime --->   23:15 | 23:30 | 23:45 | 00:00
-----------------------------------------------------------------------------------------------------------------------------
2209   |  m1     | 21/09/2018  | NULL  | NULL  | NULL  | NULL  | NULL          <---->           NULL  | NULL  | NULL  | 20586
2209   |  m1     | 20/09/2018  | 20138 | 20140 | 20143 | 20145 | 20148         <---->           20580 | 20582 | 20584 | NULL
-----------------------------------------------------------------------------------------------------------------------------

从查询中可以看出，我要求两次之间的值。我希望第二天的午夜出现在“2018-09-20”的行中，因为最后一组读数是在午夜传递的。我在午夜收到 23:45:00 到 23:59:59 的值。所以我有 96 个读数大于“2018-09-20 00:00”且小于或等于“2018-09-21 00:00”。

预期结果是：

-----------------------------------------------------------------------------------------------------------------------------
Serial | Channel | ReadingDate | 00:15 | 00:30 | 00:45 | 01:00 | 01:15  <--- ReadingTime --->   23:15 | 23:30 | 23:45 | 00:00
-----------------------------------------------------------------------------------------------------------------------------
2209   |  m1     | 20/09/2018  | 20138 | 20140 | 20143 | 20145 | 20148         <---->           20580 | 20582 | 20584 | 20586
-----------------------------------------------------------------------------------------------------------------------------

像往常一样，感谢您的支持。

标签： sqlsql-serverdatetimepivot-table

解决方案

我会让ReadingDate并ReadingTime合并为一列，因为 sql-server 中有一个 DateTime 数据类型。

如果您使用两列将很难在条件下使用。

然后您可以使用CASE WHENset ReadingDatecolumn 检查数据行是今天还是明天，如果是明天，则在行中设置今天。

在您的数据透视查询之前。

 SELECT [Serial], 
       [Channel],
       [ReadingDate],
       [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],[02:15],[02:30],[02:45],[03:00],
       [03:15],[03:30],[03:45],[04:00],[04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
       [06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],[08:15],[08:30],[08:45],[09:00],
       [09:15],[09:30],[09:45],[10:00],[10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
       [12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],[14:15],[14:30],[14:45],[15:00],
       [15:15],[15:30],[15:45],[16:00],[16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
       [18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],[20:15],[20:30],[20:45],[21:00],
       [21:15],[21:30],[21:45],[22:00],[22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00]
FROM(
    SELECT 
        Serial AS [Serial],
        Channel AS [Channel],
        (CASE WHEN CAST(ReadingDate AS DATE) > CAST(@_DateFrom AS DATE) 
            THEN CAST(@_DateFrom AS DATE) 
            ELSE CAST(ReadingDate AS DATE)
         END)  AS [ReadingDate],
        CAST(ReadingDate AS TIME) AS [ReadingTime],
        Value AS [Value]
    FROM UriData
     WHERE ReadingDate > @_DateFrom  AND ReadingDate <= @_DateTo  AND Serial = '2209'   
    ) AS [Raw]
PIVOT
(
    MAX( [Value] ) FOR [ReadingTime] IN( [00:15],[00:30],[00:45],[01:00],[01:15],[01:30],[01:45],[02:00],
                                         [02:15],[02:30],[02:45],[03:00],[03:15],[03:30],[03:45],[04:00],
                                         [04:15],[04:30],[04:45],[05:00],[05:15],[05:30],[05:45],[06:00],
                                         [06:15],[06:30],[06:45],[07:00],[07:15],[07:30],[07:45],[08:00],
                                         [08:15],[08:30],[08:45],[09:00],[09:15],[09:30],[09:45],[10:00],
                                         [10:15],[10:30],[10:45],[11:00],[11:15],[11:30],[11:45],[12:00],
                                         [12:15],[12:30],[12:45],[13:00],[13:15],[13:30],[13:45],[14:00],
                                         [14:15],[14:30],[14:45],[15:00],[15:15],[15:30],[15:45],[16:00],
                                         [16:15],[16:30],[16:45],[17:00],[17:15],[17:30],[17:45],[18:00],
                                         [18:15],[18:30],[18:45],[19:00],[19:15],[19:30],[19:45],[20:00],
                                         [20:15],[20:30],[20:45],[21:00],[21:15],[21:30],[21:45],[22:00],
                                         [22:15],[22:30],[22:45],[23:00],[23:15],[23:30],[23:45],[00:00])
) AS pvt
ORDER BY ReadingDate DESC, Channel, [Serial]

sqlfiddle

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