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go - 跳转功能

问题描述

我试图让这段代码运行，但他跳过了函数登录

package main

import "fmt"

var name string
var password string

func getName() {
    fmt.Print("What's your name : \n")
    fmt.Scanf("%s", &name)
}

func showName() {
    fmt.Print("Your name is " + name + "\n")
}

func getPassword() {
    fmt.Print("What's your password : \n")
    fmt.Scanf("%s \n", &password)
}

func singOrLog() {
    var input string
    input = ""
    var loop bool
    loop = false

    for loop == false {
        fmt.Print("Do you want to make an account or login (0 for register and 1 login) : ")
        fmt.Scanf("%s \n", &input)

        if input == "0" {
            register()
            loop = true
        } else if input == "1" {
            login()
            loop = true
        }
    }
}

func login() {
    var nameCorrect string
    nameCorrect = name
    for !(nameCorrect == name) {
        fmt.Print("What's your name :\n")
        fmt.Scanf("%s", &nameCorrect)
    }
}

func register() {
    getName()
    showName()
    getPassword()
    login()
}

func main() {
    singOrLog()
}

标签： go

解决方案

登录功能不会被跳过，尽管它永远不会打印出任何东西。该行：

nameCorrect = name

将 nameCorrect 设置为与 name 相同，后跟：

for !(nameCorrect == name) {

只有当 name 和 nameCorrect 不同时才会执行。您可以通过添加以下行来查看：

fmt.Printf("Name: '%s', nameCorrect: '%s', !(nameCorrect == name): %t\n", name, nameCorrect, !(nameCorrect == name))

这将打印：

Name: '', nameCorrect: '', !(nameCorrect == name): false

我想你不想拥有这nameCorrect = name条线。

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