首页 > 解决方案 > 添加外键约束失败。缺少约束错误代码的索引:1822

问题描述

所以我试图创建一个表'Prerequisite_to',它基本上是一个关系,它显示了哪些类被视为特定类的先决条件。这是我的 SQL 表缺陷:

CREATE TABLE Class(
infs CHAR(4) NOT NULL,
course_number CHAR(3) NOT NULL,
PRIMARY KEY (infs,course_number));

CREATE TABLE Prerequisite_to(
    infs CHAR(4),
    course_number CHAR(3),
    PRIMARY KEY (infs,course_number),
    FOREIGN KEY (infs) REFERENCES Class(infs),
    FOREIGN KEY (course_number) REFERENCES Class(course_number)
)

但是,当我执行脚本时,出现此错误:

17:29:43 创建表 Prerequisite_to( infs CHAR(4), course_number CHAR(3), PRIMARY KEY (infs,course_number), FOREIGN KEY (infs) REFERENCES Class(infs), FOREIGN KEY (course_number) REFERENCES Class(course_number) ) 错误代码:1822。添加外键约束失败。引用表 'Class' 中的约束 'prerequisite_to_ibfk_2' 缺少索引 0.00038 秒

标签: mysqlsqlmysql-workbench

解决方案


你有一个复合主键,所以你需要一个复合外键:

CREATE TABLE Prerequisite_to(
    infs CHAR(4),
    course_number CHAR(3),
    PRIMARY KEY (infs,course_number),
    FOREIGN KEY (infs, course_number) REFERENCES Class(infs, course_number)
);

仅作记录,我不喜欢复合主键。我也认为先决条件需要两个课程参考。所以:

CREATE TABLE Classes (
    class_id int auto_increment primary key,
    infs CHAR(4) NOT NULL,
    course_number CHAR(3) NOT NULL,
    unique (infs, course_number)
);

CREATE TABLE Prerequisites (
    preresequisite_id int auto_increment primary key,
    class_id int,
    prerequisite_class_id int,
    FOREIGN KEY (class_id) REFERENCES Classes(class_id),
    FOREIGN KEY (prerequisite_class_id) REFERENCES Classes(class_id)
);

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