首页 > 解决方案 > 如何使用turtle更改python onclick的背景颜色?

问题描述

我一直在尝试使用海龟在后台每次单击时触发这些颜色。如果有人可以帮助我提前感谢您的回复,那就太好了!

    import turtle
    import random


    f = turtle.pen()
    BG=turtle.Screen()
    colors = ['blue', 'red', 'yellow', 'green']
    BG.bgcolor("black")


    richard.pencolor("orange")
    richard.penup()

    def draw(x,y):
    richard.goto(x,y)
    richard.pendown()
    for x in range(360):
    richard.forward(200)
    richard.left(108)
    richard.forward(205)
    richard.left(108)
    richard.forward(210)
    richard.left(108)
    richard.forward(215)
    richard.left(1)
    richard.forward(220)
    richard.left(108)
    richard.forward(225)
    richard.left(108)
    richard.tilt(20)
    richard.speed(90)
    richard.pencolor()
    richard.pencolor(random.choice(colors))
    richard.bgcolor()
    richard.bgcolor(random.choice(colors))
    if(x % 2 ==1):
    richard.bgcolor(random.choice(colors))
    if(x % 2 ==1):
    richard.pencolor(random.choice(colors))
    richard.penup()
    BG.onclick(draw())

标签: pythonturtle-graphics

解决方案


您的主要问题是这一行:

BG.onclick(draw())

我们需要将draw函数本身传递给onclick(),而不是返回的None那个draw()

BG.onclick(draw)

单击窗口时仅更改背景颜色的简单示例:

from turtle import Screen, Turtle
from random import choice

COLORS = ['blue', 'red', 'yellow', 'green']

screen = Screen()
screen.bgcolor("black")

def draw(x, y):
    color = choice(COLORS)

    while color == screen.bgcolor():  # don't use same color twice in a row
        color = choice(COLORS)

    screen.bgcolor(color)

screen.onclick(draw)
screen.mainloop()

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