首页 > 解决方案 > 反序列化时忽略 xml 属性

问题描述

我从两个不同的系统收到一个必须用 c# 反序列化的 xml。两个 xml 应该是相同的,但不幸的是它们略有不同,我无法影响系统如何创建 xml。

xml1

<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<alarm>
  <alarmDetails>
    <dateTime>20180906-121451</dateTime>
  </alarmDetails>
  <deviceDetails>
    <deviceType>abacaxi</deviceType>
  </deviceDetails>
  <position>
    <altitude>1000</altitude>
  </position>
</alarm>

xml2

<?xml version="1.0" encoding="utf-8"?>
<alarm xmlns="http://alarm.com/xsd">
  <alarmDetails>
    <dateTime>20180906-114818</dateTime>
  </alarmDetails>
  <deviceDetails>
    <deviceType>tapioca</deviceType>
  </deviceDetails>
  <position>
    <altitude>1000</altitude>
  </position>
</alarm>

(xml 2 在警报标签上有一个附加属性)

我试图用以下方法反序列化它:

代码

using System.IO;
using System.Xml.Serialization;

namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            XmlSerializer serializer = new XmlSerializer(typeof(Alarm));
            StreamReader stream = new StreamReader("C:\\Temp\\xml1.xml");
            Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
        }
    }


    [XmlRoot(ElementName = "alarmDetails")]
    public class AlarmDetails
    {
        [XmlElement(ElementName = "dateTime")]
        public string DateTime { get; set; }
    }

    [XmlRoot(ElementName = "deviceDetails")]
    public class DeviceDetails
    {
        [XmlElement(ElementName = "deviceType")]
        public string DeviceType { get; set; }
    }

    [XmlRoot(ElementName = "position")]
    public class Position
    {
        [XmlElement(ElementName = "altitude")]
        public string Altitude { get; set; }
    }

    [XmlRoot(ElementName = "alarm")]
    public class Alarm
    {
        [XmlElement(ElementName = "alarmDetails")]
        public AlarmDetails AlarmDetails { get; set; }
        [XmlElement(ElementName = "deviceDetails")]
        public DeviceDetails DeviceDetails { get; set; }
        [XmlElement(ElementName = "position")]
        public Position Position { get; set; }
    }
}

这非常适合 xml1 但对于 xml2 我得到这个错误:

错误

System.InvalidOperationException
Message=There is an error in XML document (2,2).
Inner Exception 1:
InvalidOperationException: <alarm xmlns='http://alarm.com/xsd'> was not expected.

可能的解决方案

这一切都没有奏效..

XmlRootAttribute

From: {" 不是预期的。} 反序列化 Twitter XML

我结束了这个修改:

static void Main(string[] args)
{
    XmlRootAttribute xRoot = new XmlRootAttribute();
    xRoot.ElementName = "alarm";
    xRoot.IsNullable = true;
    XmlSerializer serializer = new XmlSerializer(typeof(Alarm), xRoot);
    StreamReader stream = new StreamReader("C:\\Temp\\xml2.xml");
    Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
}

得到与上述相同的错误。

IsNullable=true 到 XmlRoot

From: {" 不是预期的。} 反序列化 Twitter XML

[XmlRoot(ElementName = "alarm", IsNullable = true)]
public class Alarm
{ 
    [XmlElement(ElementName = "alarmDetails")]
    public AlarmDetails AlarmDetails { get; set; }
    [XmlElement(ElementName = "deviceDetails")]
    public DeviceDetails DeviceDetails { get; set; }
    [XmlElement(ElementName = "position")]
    public Position Position { get; set; }
}

与上述相同的错误。

XmlAttributeOverrides

来自:在 xml 序列化期间忽略属性,但在反序列化期间不忽略

static void Main(string[] args)
{
    XmlAttributeOverrides overrides = new XmlAttributeOverrides();
    XmlAttributes attribs = new XmlAttributes();
    attribs.XmlIgnore = true;
    attribs.XmlElements.Add(new XmlElementAttribute("alarm"));
    overrides.Add(typeof(Alarm), "alarm", attribs);
    XmlSerializer serializer = new XmlSerializer(typeof(Alarm), overrides);
    StreamReader stream = new StreamReader("C:\\Temp\\xml2.xml");
    Alarm alarmmessage = (Alarm)serializer.Deserialize(stream);
}

仍然与上述相同的错误。

建议?

我还能尝试什么来完成这项工作?是否有一些工作方法可以忽略 xmlns 属性?

标签: c#xmlxmlserializerxml-deserialization

解决方案


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