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python - 我想点击使用scrapy python的网站链接

问题描述

import scrapy
from selenium import webdriver


class QuotesSpider(scrapy.Spider):
    name = "quotes"
    start_urls = [
        'http://ozhat-turkiye.com/en/brands/a',
    ]

我想点击链接

    def __init__(self):
        self.drivers = webdriver.Firefox('C:/Program Files (x86)\Mozilla Firefox')

我想点击链接

def parse(self, response):
    for title in response.css('div.tabledivinlineblock a.tablelink50::attr(href)').extract():
        yield {'title': title,
               'response': response.url
               }

   # i want to click this a tag
    next = self.driver.find_element_by_xpath('//*[@id="maincontent_DataPager"]/a[last()]')

    # follow pagination links
    # for href in response.css('span#maincontent_DataPager a:last-child'):
    #
    #     yield response.follow(href, self.parse)

    next_page = response.css('span#maincontent_DataPager a:last-child::attr(href)').extract_first().strip()
    if next_page is not None:
        yield response.follow(next_page, callback=self.parse)

标签： pythonseleniumselenium-webdriverweb-scrapingscrapy

解决方案

以下脚本应该为您获取所需的项目，耗尽连接到下一页链接的所有点击。您不能在此处使用，response.follow()因为除了单击它之外没有可关注的链接。

import time
import scrapy
from selenium import webdriver

class QuotesSpider(scrapy.Spider):
    name = "quotes"
    start_urls = [
        'http://ozhat-turkiye.com/en/brands/a',
    ]

    def __init__(self):
        self.driver = webdriver.Firefox()

    def parse(self, response):
        self.driver.get(response.url)
        while True:
            time.sleep(5)
            for title in self.driver.find_elements_by_css_selector('div.tabledivinlineblock a.tablelink50'):
                yield {'title': title.text,'response': response.url}

            try:
                self.driver.find_element_by_css_selector('span#maincontent_DataPager a:last-child').click()
            except Exception: break

我在脚本中使用了硬编码等待，这根本不推荐。您应该将其替换为Explicit Wait.

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