首页 > 解决方案 > Microsoft Excel VBA 连接到多个 Microsoft Access DB

问题描述

我目前正在尝试连接到 2 个单独.mdb的文件并执行INNER JOIN.

所以,我有 2 个 .mdb ( Sample1.mdb& Sample2.mdb)。两者都受密码保护。

当我尝试连接时,它显示一个错误,指出"it's already opened exclusively by another user, or you need permission...".

是否因为我没有password在此语句中插入属性而发生错误?如果是,我如何password在此语句中插入属性?

[Excel 8.0;HDR=YES;IMEX=2;DATABASE=" & Application.ActiveWorkbook.Path & "\Sample1.mdb]?

这是我的整个示例代码:

Dim Conn As ADODB.Connection
Dim resultSet As ADODB.Recordset

Set Conn = New ADODB.Connection

sqlStatement = "SELECT * FROM [Excel 8.0;HDR=YES;IMEX=2;DATABASE=" &
Application.ActiveWorkbook.Path & "\Sample1.mdb].[SampleData$] a INNER JOIN 
[Excel 8.0;HDR=YES;IMEX=2;DATABASE=" & Application.ActiveWorkbook.Path &
"\Sample2.mdb].[SampleInfo$] b ON a.Index = b.Index WHERE a.idCode = 2"

     With Conn
            .Provider = "Microsoft.ACE.OLEDB.12.0"
            .ConnectionString = Application.ActiveWorkbook.Path + "\Sample2.mdb"
            .Properties("Jet OLEDB:Database Password") = "password"
            .Open

             Set resultSet = .Execute(sqlStatement)
         End With

标签: vbaexcelms-access

解决方案


这有一些奇怪的事情。

  1. [Excel 8.0;HDR=YES;IMEX=2;是连接到 Excel 文件而不是 MDB 数据库的连接字符串。由于您将 MDB 数据库作为参数传递给它,因此肯定会出现奇怪的错误。由于连接到 Access 是 Access 本机的,因此您只需要指定路径。
  2. 我会在连接字符串中指定所有连接参数,包括 uid。
Dim Conn As ADODB.Connection
Dim resultSet As ADODB.Recordset

Set Conn = New ADODB.Connection

sqlStatement = "SELECT * FROM [" &
Application.ActiveWorkbook.Path & "\Sample1.mdb].[SampleData$] a INNER JOIN [SampleInfo$] b ON a.Index = b.Index WHERE a.idCode = 2"

     With Conn
            .Provider = ""
            .ConnectionString = "Provider=Microsoft.ACE.OLEDB.12.0;User ID=Admin;Data Source="Application.ActiveWorkbook.Path + "\Sample2.mdb;Jet OLEDB:Database Password=""password"""
            .Open
             Set resultSet = .Execute(sqlStatement)
         End With

要使用密码查询 Access 数据库,请在 ISAM 连接字符串中指定密码:

"SELECT * FROM [MS Access;PWD=password;DATABASE=" &
Application.ActiveWorkbook.Path & "\Sample1.mdb].[SampleData$] a INNER JOIN 
[MS Access;PWD=password;DATABASE=" & Application.ActiveWorkbook.Path &
"\Sample2.mdb].[SampleInfo$] b ON a.Index = b.Index WHERE a.idCode = 2"

当然,您需要确保对两个 MDB 数据库使用正确的连接字符串:在当前代码中,Sample2 受到保护但 Sample1 不受保护,Sample2 受加密保护(仅提示密码),而不是用户级安全性(提示密码和用户名)。


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