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python - 以不同格式对 IP 地址进行排序

问题描述

我试图得到：

['192.168.70.19 (tcp/1433)']
['192.168.70.223 (tcp/1051),192.168.70.19 (tcp/1025), 192.168.70.245 (tcp/1051)'] 
['192.168.70.19 (tcp/3389),192.168.70.223 (tcp/3389)']

至

['192.168.70.19 (tcp/1433)']
['192.168.70.19 (tcp/1025),192.168.70.223 (tcp/1051), 192.168.70.245 (tcp/1051)'] 
['192.168.70.19 (tcp/3389),192.168.70.223 (tcp/3389)']

这是我的代码，它不正确。由于想要保留 tcp 部分，我无法对 IP 地址进行排序。有没有人对此有更好的建议或解决方案。任何想法，将不胜感激。

import re
a=['192.168.70.19 (tcp/1433)', '192.168.70.223 (tcp/1051),192.168.70.19 (tcp/1025),192.168.70.245 (tcp/1025)', '192.168.70.19 (tcp/3389),192.168.70.223 (tcp/3389)']


for z in a:
    if z.find(','):
        #removes tcp part (but I want to keep)        
        #b = re.sub(r'\(.*?\)', '', z)

        #I can sort the IP with this, but it doesnt have the tcp part.
        #z.sort(key=lambda s: map(int, s.split('(')[0].split('.')))

标签： pythonsorting

解决方案

这是一个没有正则表达式的解决方案

[','.join(sorted(x.split(','), key= lambda x: x.split()[0])) for x in a]

要对 IP+TCP 组合进行排序，请使用该元组的第一部分对 ip addr 进行排序

输出：

['192.168.70.19 (tcp/1433)', 
'192.168.70.19 (tcp/1025),192.168.70.223 (tcp/1051),192.168.70.245 (tcp/1025)', 
'192.168.70.19 (tcp/3389),192.168.70.223 (tcp/3389)']

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