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java - Json无法反序列化Spring中的实例错误

问题描述

我正在尝试发送一个 json 长列表并从数据库中获取记录。

我的控制器是：

@Api(tags = Endpoint.RESOURCE_customer, description = "customer Resource")
@RestController
@RequestMapping(produces = MediaType.APPLICATION_JSON_VALUE,consumes = MediaType.APPLICATION_JSON_VALUE)
@ResponseStatus(HttpStatus.OK)
public class CustomerResourceController {

    private final customerService customerService;


    public CustomerResourceController(customerService customerService) {

        this.customerService = customerService;
    }

    @ApiOperation(
            value = "Return customer",
            response = customerDto.class, responseContainer="List"
    )
    @PostMapping(value = Endpoint.RRESOURCE_customer_ID)
    public List<customerDto> getCustomersByIds(@RequestBody List<Long> ids) {
        return customerService.findcustomerIds(ids);
    }

}

客户端类是：

@Headers("Content-Type: " + MediaType.APPLICATION_JSON_VALUE)
public interface CustomerClient {

@RequestLine("POST /customer/customers/search")
    List<LocGrpDto> getCustomersByIds(@RequestBody @Validated List<Long> ids);
}

我用 JSON 在邮递员中测试了这个服务：

{“ID”：[1,7,8] }

但我得到这个错误：

{
    "timestamp": "2018-10-05T13:29:57.645+0000",
    "status": 400,
    "error": "Bad Request",
    "message": "Could not read document: Can not deserialize instance of java.util.ArrayList out of START_OBJECT token\n at [Source: java.io.PushbackInputStream@3cb8b584; line: 1, column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of java.util.ArrayList out of START_OBJECT token\n at [Source: java.io.PushbackInputStream@3cb8b584; line: 1, column: 1]",
    "path": "/api/v1/customer/customers/search",
    "errors": []
}

问题是什么？您是否在这里看到任何问题，或者可能是由于我的服务类或 dto 类引起的？

标签： javajsonspringhttp

解决方案

尝试使用有效负载请求[1,7,8]，而不是{"ids": [1,7,8]}.

您的 JSON 将转换为具有下一种格式的请求正文。

class Body {

    private List<Long> ids;

    // constructor, getters and setters 

}

对于 REST 客户端，您可以查看RestTemplate.

RestTemplate template;
List<Long> ids;
List<CustomerDto> = template.exchange(
            "/customer/customers/search",
            HttpMethod.POST,
            new HttpEntity<>(ids),
            new ParameterizedTypeReference<List<CustomerDto>>() {}).getBody()

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