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python - Opening file in Python 3.4.2 shell

问题描述

I am using Python 3.4.2 on Windows 10 and am just getting into opening and read/writing to files from the Python shell

I did this test and got the following error message in spite of the fact that I had created the file beforehand (but not from the shell as that would not work either).

Can someone tell me what I haven't taken into consideration here because all my searches tell me this should work.

>>> import os
>>> helloFile = open('C:\\Users\\jennifer\\Hello.txt')
Traceback (most recent call last):
  File "<pyshell#6>", line 1, in <module>
    helloFile = open('C:\\Users\\jennifer\\Hello.txt')
FileNotFoundError: [Errno 2] No such file or directory: 'C:\\Users\\jennifer\\Hello.txt'

I did as John Gordon suggested and removed .txt from the pathname and it still didn't work.

Here is the directory and path for the file:

C:\Users\jennifer\Desktop\Hello

Finally, it has opened and will be very aware of the need to call the complete path in the future! Thank you

标签： python

解决方案

您只需要在 Drive 后加上一个“\”，这是为了避免 unicode 错误。下面的代码假设您已经在 Powershell（Window 的 CMD）中运行了 Python。

此外，如果您想读取文件（即打印 CMD 中的内容），您需要通过将 r 放在文件路径之前使其可读。

file =open(r,'C:\\Users\jennifer\Desktop\Hello.txt')

要打印内容：

for i in file:
    print(i)

然后按两次 Enter 以获取输出。

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