c# - 我可以消除以下派生类的重复代码并移至抽象基类吗

Question

我有一个抽象基类，开始一个timer所有派生类共有的，

public abstract class BaseClass
{
    public virtual void Start() { _timer.Start(); }
}

现在我需要为每个派生类加载不同的 JSON 配置文件并创建文件，

public class DerivedClass1 : BaseClass
{
    private readonly List<config> configs = new List<config>();

    public DerivedClass1()
    {
        configs = JsonSettings.GetConfigurations(@"./Configurations/1.json");
    }
    public override void Start()
    {
        base.Start();

        foreach (var configuration in configs)
        {
            JsonSettings.CreateConfigFile(configuration);
        }
    }
}

public class DerivedClass2 : BaseClass
{
    private readonly List<config> configs = new List<config>();

    public DerivedClass2()
    {
        configs = JsonSettings.GetConfigurations(@"./Configurations/2.json");
    }
    public override void Start()
    {
        base.Start();

        foreach (var configuration in configs)
        {
            JsonSettings.CreateConfigFile(configuration);
        }
    }
}

正如我所见，有很多代码在各种派生类中重复。

我可以移动这些代码以及abstract base类还是有其他方法？

标签： c#inheritance

Answer 1

我认为您可以将代码简化为：

public abstract class BaseClass
{
    protected virtual List<config> configs { get; set; } = new List<config>();
    public virtual void Start()
    {
        _timer.Start();
        foreach (var configuration in configs)
        {
            JsonSettings.CreateConfigFile(configuration);
        }
    }
}

public class DerivedClass1 : BaseClass
{
    public DerivedClass1()
    {
        configs = JsonSettings.GetConfigurations(@"./Configurations/1.json");
    }
}

public class DerivedClass2 : BaseClass
{
    public DerivedClass2()
    {
        configs = JsonSettings.GetConfigurations(@"./Configurations/2.json");
    }
}