spring-boot - 如何使用 Spring Data JPA 实现自定义存储库？

问题描述

我正在尝试使用 Spring Data 实现自定义存储库，但出现以下异常：

原因：org.springframework.data.mapping.PropertyReferenceException：找不到类型 {Entity} 的属性 {name}

看起来@NoRepositoryBean工作不正常，Spring 正在扫描用它注释的接口，有谁知道如何以正确的方式进行操作？

所有存储库的自定义方法。

@NoRepositoryBean
public interface BaseRepository<T, ID> extends JpaRepository<T, ID> {
    List<T> findAll(Company company);

    EntityManager getEntityManager();
}

public class BaseRepositoryImpl<T, ID> extends SimpleJpaRepository<T, ID> implements BaseRepository<T, ID> {
    private EntityManager entityManager;

    public BaseRepositoryImpl(JpaEntityInformation<T, ?> entityInformation, EntityManager entityManager) {
        super(entityInformation, entityManager);
        this.entityManager = entityManager;
    }

    public EntityManager getEntityManager() {
        return entityManager;
    }

    public List<T> findAll(Company company) {
        //Search by company
    }
}

我还有一些具有自定义方法的存储库，例如：

@NoRepositoryBean
public interface QuestionCustomRepository {
    List<Question> findAllQuestionByTypeAndAsset(Integer[] assetIds);
}

public interface QuestionRepository extends BaseRepository<Question, Integer>, QuestionCustomRepository {
}

@Repository
public class QuestionCustomRepositoryImpl extends BaseRepositoryImpl<Question, Integer> implements QuestionCustomRepository {
    public QuestionCustomRepositoryImpl(JpaEntityInformation<Question, ?> entityInformation, EntityManager entityManager) {
    super(entityInformation, entityManager);
    }

    @Override
    public List<Question> findAllQuestionByTypeAndAsset(Integer[] assetIds) {
    EntityManager entityManager = getEntityManager();
    // Call Native Query
    }
}

测试

@RunWith(SpringRunner.class)
@SpringBootTest(classes = SpringBaseTest.SpringConfiguration.class, properties = "logging.level.org.springframework.data=DEBUG")
@DataJpaTest
public class SpringBaseTest {
    @SpringBootApplication
    @EntityScan(basePackageClasses = Question.class)
    @EnableJpaRepositories(basePackageClasses = QuestionRepository.class, repositoryBaseClass = BaseRepositoryImpl.class)
    public static class SpringConfiguration {
    }
}

class QuestionRepository extends SpringBaseTest {
    @Inject
    QuestionRepository questionRepository;

    @Test
    public void testFindAllByAssetIts() throws Exception {
        List<Question> list = questionRepository.findAllQuestionByTypeAndAsset(new Integer[]{1,2,3});

        assertThat(list).hasSize(3);
    }
}

感谢任何帮助，谢谢。

标签： spring-bootspring-data-jpa

spring-boot - 如何使用 Spring Data JPA 实现自定义存储库？

问题描述

解决方案

推荐阅读