python-2.7 - 防止 Python 中的滑动窗口在使用 islice 时跳过范围

Question

使用 islice 实现每张幻灯片按 10 个索引移动 10 个样本的滑动窗口时遇到问题。

我的文本文件（input.txt）在每一行“一、二、三……”上都有数字值，以便于识别行索引。

这是我正在使用的代码：

with open("input.txt", "r") as text_file:
    for n in range (0,29,10):
        window_string = ''
        x = n
        for line in itertools.islice(text_file, x, x+10):
            window_string = window_string + line
        print str(x) + " to " + str(x+10)
        Stream=window_string.replace('\n', ' ')
        print Stream +'\n'

这就是正在输出的内容：

0 to 10
zero one two three four five six seven eight nine 

10 to 20
twenty twenty-one twenty-two twenty-three twenty-four twenty-five twenty-six twenty-seven twenty-eight twenty-nine

20 to 30

而不是预期的：

0 to 10
zero one two three four five six seven eight nine 

10 to 20
ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen

20 to 30
twenty twenty-one twenty-two twenty-three twenty-four twenty-five twenty-six twenty-seven twenty-eight twenty-nine

请让我知道迭代 n 的问题是什么。

标签： python-2.7

Answer 1

一直没搞清楚上面的问题是什么。决定改为将文件读入列表，然后在列表上实现滑动窗口。这是我最终使用的代码

lines = [line.rstrip('\n') for line in open('twitter-out2.txt')]
#print lines
for n in range (0,29,10):
        streamer = ' '.join(lines[n:n+10])
        print "from " + str(n) + " to " + str(n+10)
        print streamer

输出如预期：

from 0 to 10
zero one two three four five six seven eight nine
from 10 to 20
ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen
from 20 to 30
twenty twenty-one twenty-two twenty-three twenty-four twenty-five twenty-six twenty-seven twenty-eight twenty-nine