时间戳

首页 > 解决方案 > Django 错误（属性）：“CharField”对象没有属性“is_related”

python - Django 错误（属性）：“CharField”对象没有属性“is_related”

问题描述

我正在尝试在我的新项目中向每个用户进行描述。但是当我尝试进行迁移时出现错误。我不知道如何解决它。我尝试了不同的东西，但没有任何效果，我的编码可能非常糟糕，但我也是 python 和 django 的新手。

错误：

C:\Users\bruger\Dropbox\min-login-web\web_login>python manage.py makemigrations
Traceback (most recent call last):
  File "manage.py", line 15, in <module>
    execute_from_command_line(sys.argv)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\__init__.py", line 381, in execute_from_command_line
    utility.execute()
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\__init__.py", line 375, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\base.py", line 316, in run_from_argv
    self.execute(*args, **cmd_options)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\base.py", line 353, in execute
    output = self.handle(*args, **options)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\base.py", line 83, in wrapped
    res = handle_func(*args, **kwargs)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\core\management\commands\makemigrations.py", line 143, in handle
    loader.project_state(),
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\migrations\loader.py", line 322, in project_state
    return self.graph.make_state(nodes=nodes, at_end=at_end, real_apps=list(self.unmigrated_apps))
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\migrations\graph.py", line 378, in make_state
    project_state = self.nodes[node].mutate_state(project_state, preserve=False)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\migrations\migration.py", line 87, in mutate_state
    operation.state_forwards(self.app_label, new_state)
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\migrations\operations\models.py", line 85, in state_forwards
    list(self.managers),
  File "C:\Users\bruger\AppData\Local\Programs\Python\Python37\lib\site-packages\django\db\migrations\state.py", line 377, in __init__
    if field.is_relation and hasattr(field.related_model, '_meta'):
AttributeError: 'CharField' object has no attribute 'is_relation'

我的模型文件：

from django import forms
from django.db import models
from django.db.models.signals import post_save
from django.contrib.auth.models import User
from PIL import Image


class Profile(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    image = models.ImageField(default='default.jpg', upload_to='profile_pics')

    def __str__(self):
        return f'{self.user.username} Profile'

    def save(self):
        super().save()

        img = Image.open(self.image.path)

        if img.height > 300 or img.width > 300:
            output_size = (300, 300)
            img.thumbnail(output_size)
            img.save(self.image.path)

class Desc(models.Model):
    description = forms.CharField(widget = forms.Textarea, max_length = 250, required=False)

    def __str__(self):
        return f'{self.user.username} Desc'

我希望有人能帮助我，因为这真的让我很紧张。

标签： pythondjangoformsattributeerror

解决方案

你混合形式和模型。模型不指定（HTML）表单，它指定数据库应如何存储数据，因此您需要使用models.CharField：

class Desc(models.Model):
    description = models.CharField(max_length=250)

这样CharField没有widget分配给它，这是您应该在表单级别处理的事情。

您可能需要进行迁移，因为到目前为止，您的模型description中还没有字段。Desc

我在某种程度上同意，表单经常有一个同名的字段是令人困惑的（这些通常是同名模型字段的默认表单字段）。然而，这个想法是模型字段指定数据库中的列，而表单字段指定（HTML）表单中的文本框、复选框等。

推荐阅读